What is the magnitude of the net force on the block (the moment it is released?
1 answer:
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Answer:
0·95
Explanation:
Given the combined mass of the rider and the bike = 100 kg
Percent slope = 12%
∴ Slope = 0·12
Terminal speed = 15 m/s
Frontal area = 0·9 m²
Let the slope angle be β
tanβ = 0·12
As it attains the terminal speed, the forces acting on the combined rider and the bike must be balanced and therefore the rider must be moving download as the directions of one of the component of weight and drag force will be in opposite directions
The other component of weight will get balance by the normal reaction and you can see the figure which is in the file attached
From the diagram m × g × sinβ = drag force
Drag force = 0·5 × d × × v² × A
where d is the density of the fluid through which it flows
is the drag coefficient
v is the speed of the object relative to the fluid
A is the cross sectional area
As tanβ = 0·12
∴ sinβ = 0·119
Let the fluid in this case be air and density of air d = 1·21 kg/m³
m × g × sinβ = 0·5 × d × × v² × A
100 × 9·8 ×0·119 = 0·5 × 1·21 × × 15² × 0·9
∴ ≈ 0·95
∴ Drag coefficient is approximately 0·95
Answer:
The wavelength is
Explanation:
From the question we are told that
The thickness is
The refractive index of the non-reflective coating is
The refractive index of glass is
Generally the condition for destructive interference is mathematically represented as
Where
is the angle of refraction which is 0° when the light is strongly transmitted
and n is the order maximum interference
so
at the point n = 1
at n =2
Now we know that the wavelength range of visible light is between
So the wavelength of visible light that is been transmitted is