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True [87]
3 years ago
12

When you are driving on a rural road, if your right wheels run off the pavement, you should hold the steering wheel firmly and

Physics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

C). Take your foot off the gas pedal. Then brake lightly until you are moving at low speed.                    

Explanation:

While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the gas pedal, then apply brake lightly until we are moving at a low speed.

      When our wheels drift off the pavement area, we should not panic and yank. And instead of turning the wheel back in the left direction towards the road, it is always safer to take off our foot from the gas pedal and then apply brakes slowly. When our vehicle slows down check the incoming traffic behind us and then we should slowly move back on to the pavement.

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A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10 m/s. The instan
gizmo_the_mogwai [7]

Answer:

The velocity just before hitting the ground is v_f = 30 m/s

Explanation:

From the question we are told that

    The initial speed is  u = 10 m/s

    The final speed is  v = 30 \ m/s

From the equations of motion we have that

      v^2 =u^2 + 2as

Where s is the distance travelled which is the height of the cliff

  So making it the subject of the the formula  we have that

        s = \frac{v^2 - u^2 }{2a}

Where a is the acceleration due to gravity with a value  a = 9.8m/s^2

       So

                  s = \frac{30^2 - 10^2 }{2 * 9.8 }

                  s = 40.8 \ m

Now we are told that was through horizontally with a speed of

      v_x =10 m/s

Which implies that this would be its velocity horizontally through out the motion

    Now it final  velocity vertically can be mathematically evaluated as

            v_y = \sqrt{2as}

Substituting values

             v_y = \sqrt{(2 * 9.8 * 40.8)}

             v_y =  28.3 \ m/s

The resultant final velocity is mathematically evaluated as

       v_f = \sqrt{v_x^2 + v_y^2}

Substituting values

       v_f = \sqrt{10^2 + 28.3^2}

       v_f = 30 m/s

   

5 0
3 years ago
A playground merry-go-round of radius R = 1.40 m has a moment of inertia I = 265 kg · m2 and is rotating at 11.0 rev/min about a
Tom [10]

Answer:

The value of new value of angular speed of merry go round.\omega_{2} = 0.96 \frac{rad}{sec}

Explanation:

Given data

r = 1.4 m

Moment of inertia I_{1} = 265 kg - m^{2}

N_{1} = 11 RPM

\omega_{1} = \frac{2 \pi N}{60}

\omega_{1} = \frac{2 \pi (11)}{60}

\omega_{1} = 1.15 \frac{rad}{sec}

From conservation of momentum principal

I_{1} \omega_{1}  = I_{2} \omega_{2} ------- (1)

I_{2} = m r^{2} + 265

I_{2} = 27 (1.4)^{2} + 265

I_{2} = 317.92 \ kg m^{2}

Put all the values in equation  (1)

265 × 1.15 = 317.92 × \omega_{2}

\omega_{2} = 0.96 \frac{rad}{sec}

This is the value of new value of angular speed of merry go round.

6 0
3 years ago
What is the difference between 3.15 m and 2.006 m with the correct number of significant figures
snow_lady [41]
The differences is 1.144
5 0
3 years ago
Read 2 more answers
After a wave passes through a medium, particles in the medium
sertanlavr [38]

Answer:

If a particle is affected by a wave, then the particles are displaced. They move along the direction of the wave. Hence, After a wave passes through a medium, particles in the medium are moved along with the wave.

Explanation:

hope this helps you

3 0
2 years ago
A brick falls from a wall to the ground 3.42 m below. How much time will it take to
ddd [48]

Answer:

The time taken by the brick to hit the ground, t = 0.84 s

Explanation:

Given that,

A brick falls from a height, h = 3.42 m

The initial velocity of the brick is zero.

Since the brick is under free-falling. The time equation of a free-falling body when the displacement is given is

                                     t = \sqrt{2h/g}

where,

                                 h - height from surface in meters

                                 g - acceleration due to gravity

on substituting the values in the above equation,

                                 t =  \sqrt{2X3.14/9.8}

                                   = 0.84 s

Hence, time taken by the brick to hit the ground is t = 0.84 s

6 0
3 years ago
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