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3 years ago

When you are driving on a rural road, if your right wheels run off the pavement, you should hold the steering wheel firmly and

Physics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

C). Take your foot off the gas pedal. Then brake lightly until you are moving at low speed.

Explanation:

While driving on roads of rural areas, if our right wheel moves off the pavement, we should always hold the steering wheel firmly and then take our foot off the gas pedal, then apply brake lightly until we are moving at a low speed.

When our wheels drift off the pavement area, we should not panic and yank. And instead of turning the wheel back in the left direction towards the road, it is always safer to take off our foot from the gas pedal and then apply brakes slowly. When our vehicle slows down check the incoming traffic behind us and then we should slowly move back on to the pavement.

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Calculate the flow rate of blood (of density 0.846 g/cm3 ) in an aorta with a crosssectional area of 1.36 cm2 if the flow speed

Roman55 [17]

Answer:

55.80 g/s

Explanation:

From the question,

Flow rate = density×Area×velocity.

φ = ρ×A×V................... Equation 1

Where φ = flow rate of blood, ρ = density of blood, A = cross sectional area of blood, V = velocity of blood.

Given: ρ = 0.846 g/cm³, A = 1.36 cm², V = 48.5 cm/s.

Substitute these values into equation 1

φ = 0.846×1.36×48.5

φ = 55.80 g/s

Hence, the flow rate of the blood = 55.80 g/s

6 0

3 years ago

Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter

kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

$T_e=2\pi \sqrt{\frac{L}{g_e}}$

where

$g_e = 9.8 m/s^2$ is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

$T_m=2\pi \sqrt{\frac{L}{g_m}}$

where

$g_m = 1.6 m/s^2$ is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

$\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}$

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

#LearnwithBrainly

6 0

3 years ago

A piano tuner uses a tuner to create a tone of 5.00 x 10² Hz. When a key on the piano is struck he hears 5 beats per second. Wha

Grace [21]

Yo answer is 605 hz that is the average hz of a piano

6 0

2 years ago

Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?

jenyasd209 [6]

Explanation:

the wavelengths get shorter

3 0

2 years ago

Olaf is standing on a sheet of ice that covers the football stadium parking lot in Buffalo, New York; there is negligible fricti

Bas_tet [7]

Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

$mv_{1i}+Mv_{2i}=(m+M)v$ (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

$v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}$

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

3 0

2 years ago