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Sati [7]
3 years ago
5

After the ball has left the bat, and while it is traveling upward (at point P in the figure (Figure 1) ), what is the direction

of acceleration (Figure 2) ? Ignore air resistance.
Physics
2 answers:
posledela3 years ago
7 0

Answer:

during the motion of the ball the acceleration is due to gravity which is always downwards.

Explanation:

While ball is moving upwards after being hit by the bat then the net force on the ball is given as

F = - F_g

so here the negative sign shows that direction of force is opposite to the direction of velocity which is downwards

so we have

a = - g

a = - 9.81 m/s^2

so during the motion of the ball the acceleration is due to gravity which is always downwards.

ss7ja [257]3 years ago
4 0
From the moment the ball leaves the bat until the moment the ball hits the ground, its acceleration is 9.8 m/s^2 directed downward. That's the acceleration of gravity.
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A sinusoidal voltage is given by the expression ????(????)=20cos(5π×103 ????+60°) V. Determine its (a) frequency in hertz, (b) p
MA_775_DIABLO [31]

<em>There are some placeholders in the expression, but they can be safely assumed</em>

Answer:

(a) f=1617.9\ Hz

(b) T=0.618\ ms

(c) A=20 \ Volts

(d) \varphi=60^o

Explanation:

<u>Sinusoidal Waves </u>

An oscillating wave can be expressed as a sinusoidal function as follows

V(t)&=A\cdot \sin(2\pi ft+\varphi )

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A=Amplitude

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The voltage of the question is the sinusoid expression  

V(t)=20cos(5\pi\times 103t+60^o)

(a) By comparing with the general formula we have

f=5\pi\times 103=1617.9\ Hz

\boxed{f=1617.9\ Hz}

(b) The period is the reciprocal of the frequency:

\displaystyle T=\frac{1}{f}

\displaystyle T=\frac{1}{1617.9\ Hz}=0.000618\ sec

Converting to milliseconds

\boxed{T=0.618\ ms}

(c) The amplitude is

\boxed{A=20 \ Volts}

(d) Phase angle:

\boxed{\varphi=60^o}

4 0
3 years ago
The elastic energy stored in your tendons can contribute up to 35 % of your energy needs when running. Sports scientists have st
irina [24]

Complete Question:

The elastic energy stored in your tendons can contribute up to 35 % of your energy needs when running. Sports scientists have studied the change in length of the knee extensor tendon in sprinters and nonathletes. They find (on average) that the sprinters' tendons stretch 43 mm , while nonathletes' stretch only 32 mm . The spring constant for the tendon is the same for both groups, 31 {\rm {N}/{mm}}. What is the difference in maximum stored energy between the sprinters and the nonathlethes?

Answer:

\triangle E = 12.79 J

Explanation:

Sprinters' tendons stretch, x_s = 43 mm = 0.043 m

Non athletes' stretch, x_n = 32 mm = 0.032 m

Spring constant for the two groups, k = 31 N/mm = 3100 N/m

Maximum Energy stored in the sprinter, E_s = 0.5kx_s^2

Maximum energy stored in the non athletes, E_m = 0.5kx_n^2

Difference in maximum stored energy between the sprinters and the non-athlethes:

\triangle E = E_s - E_n = 0.5k(x_s^2 - x_n^2)\\\triangle E = 0.5*3100* (0.043^2 - 0.032^2)\\\triangle E = 0.5*31000*0.000825\\\triangle E = 12.79 J

4 0
3 years ago
Joaquin has hockey practice at the same ice rink where Alton has curling practice. One day, they were both playing on the ice wi
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the puck recoils in each case.

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3 years ago
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Impulse equals?<br> A) momentum x velocity<br> B) momentum x time<br> C) mass x velocity
mina [271]

Answer:

B

Explanation:

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A bus is moving in astraight line at speed of 25m/s. What time does bus take to cover 5 km
WARRIOR [948]

Answer:

Kinematics

given,

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Explanation:

I Hope you Guys Understood

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