1. Which of the following rules determines the charge on a monatomic Ion formed from a nonmetal?C. 8 - group number
2. Which of the following statements is true?
A. Metals lose electrons to become cations.
<span>200 moles
The balanced equation for creating water from hydrogen and oxygen gas is
2H2 + O2 => 2H2O
So for every mole of oxygen gas, you need two moles of hydrogen. So looking that the amount of oxygen and hydrogen you have, it's obvious that oxygen is the limiting reactant since 100 moles of oxygen will consume 200 moles of hydrogen. While 210 moles of hydrogen requires 105 moles of oxygen.
Now for each mole of oxygen gas you use, you create 2 moles of water. So
100 mol * 2 = 200 mol
So you can create 200 moles of water from the given amounts of reactants.</span>
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Answer:
Hello, Im Mack. Hope you're doing well. :)
Here is my Correct, custom answer for the lab Question, (I also took the same assignment and got a 100% score)
Explanation:
The heating of the sodium acetate solution made it change from super-saturated to un-saturated. Yet now that it cooled back to room temperature Im sure it is saturated. it wasn't able to disolve the excess sodium acetate left over at room temperature and had to be heated so now that it is back to room temperature I Think it will not disolve the sodium acetate left in the solution until it is heated again.
Hope this helped you out,
Please feel free to comment for further help, and I'll reply asap.
<u>Have a great day my friend :)</u>
Answer:
Please see the complete formt of the question below
Chlorine gas can be made from the reaction of manganese dioxide with hydrochloric acid.
MnO₂(s) + HCl(aq) → MnCl₂(aq) + H₂O(l) + Cl₂(g)
According to the above reaction, determine the limiting reactant when 5.6 moles of MnO₂ are reacted with 7.5 moles of HCl.
The answer to the above question is
The limiting reactant is the MnO₂
Explanation:
To solve this, we note that one mole of MnO₂ reacts with one mole of HCl to produce one mole of MnCl₂, one mole of H₂O and one mole of Cl₂
Molar mass of MnO₂ = 86.9368 g/mol
Molar mass of HCl = 36.46 g/mol
From the stoichiometry of the reaction, 5.6 moles of MnO₂ will react with 5.6 moles of HCl to produce 5.6 moles of H₂O and 5.6 moles of Cl₂
However there are 7.5 moles of HCL therefore there will be an extra 7.5-5.6 or 1.9 moles of HCl remaining when the reaction is completed
