1 kg =1000 g = 10³ g,
1 m = 100 cm ,
(1m)³ = (100 cm)³= (10²)³ cm³ = 10⁶ cm³ or 10⁶ mL
5,427 kg/m³ = <span>5,427 kg/ 1m³ = (5427 * 10³ g)/ 10⁶ mL=5427/10³ g/mL=
=5427/1000 g/mL = 5.427 g/mL
</span>5.427 g/mL is density of Mercury, and 1.0 g/mL is density of water.
Density of Mercury is more then density of the water, so
mercury will sink in the water.
Answer is: <span>A. 18.02 g/mol.
At standard temperature and pressure 1 mol of gas occupied 22.4 liters:
V(H</span>₂O) = 22.4 L; volume of water.
Vm = 22.4 L/mol; molar volume at STP.
n(H₂O) = V ÷ Vm.
n(H₂O) = 22.4 L ÷ 22.4 L/mol.
n(H₂O) = 1 mol; amount of substance (water).
M(H₂O) = Ar(O) + 2Ar(H) · g/mol.
M(H₂O) = 16 + 2 ·1.01 · g/mol.
M(H₂O) = 18.02 g/mol; molar mass of water.
18.998403
Explanation:
The internet told me
Answer:
2 molecules of water represents 3.32 x 10^-24 moles of water.
Explanation:
To find the solution to this problem, you have to use the concept of Avogadro´s number, that is in 1 mol of any element o compound there are 6.022 x 10^23 molecules. Then,
1 mol H2O ------------- 6.022 x 10^23 molecules
x= 3.32 x 10^-24 ---- 2 molecules.
2 molecules of water represents 3.32 x 10^-24 moles of water.
Answer:
c. The reaction will proceed rapidly from left to right.
Explanation:
The variation of the free Gibbs energy doesn't tell anything about the speed of reaction.
On the other hand, when ΔGo is negative: the reaction is spontaneous, thermodynamically favourable, and the products are more stable than the reactants
