Answer:
5-chloro-2-methylcyclohexanol
Explanation:
There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.
IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. <em><u>In this case, the priority functional group is the alcohol group</u></em>, <u><em>so we will start the counting of the carbons in this group.</em></u> Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, <em><u>in this case, we can assign the number 2 to the methyl group and 5 to the chloride group</u></em>, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.
Since the other options involve: <u>high countings for the susbtituents groups (</u><u>3</u><u>-chloro-</u><u>6</u><u>-methylcyclohexanol)</u>, <u>wrong assignation of priority functional group (</u><u>1-chloro</u><u>-4-methylcyclohexanol), wrong sequence of counting in the compound (</u><u>2-methyl-3-chloro</u><u>cyclohexanol) and no alphabetical order to name the compound (2-</u><u>methyl</u><u>-5-</u><u>chloro</u><u>cyclohexanol), </u><u>the correct option is:</u>
5-chloro-2-methylcyclohexanol
Have a nice day!
Answer:
5. 2 Al 3 Cl2 and 2 AlCl3
Cl2 is limiting
(It has the highest coefficients, but that's not always true. If they give you the number of grams for each make sure to work the math out)
6. C
(As the pressure increases there is less volume for the molecules to move around, therefore the molecules will be closer together, allowing for more collisions.)
7. b
(if the temperature is increases so will the rate of the reaction. The increase in temperature will allow for the molecules to move at a faster rate, allowing for more collisions (reactions) between them.
8. d
(dynamic equilibrium is the state at which the reaction is consistently moving, there fore the amounts should remain the same)
9. A
(a catalyst will lower the the pathway of activation energy because it's meant to speed up a reaction)
bro youre on your own after this, im tired
Earnest Rutherford was JJ Thomson’s student. He disproved Thomson’s plum pudding model. So Rutherford comes after Thomson. Dalton is first because you should be aware of Daltons atomic theory on the atom. He was one of the first people to actually make a theory about atoms in that type of detail. Bohr came last. I forgot what Bohr’s model was, but you can do a quick google search if you want.
So your answer is B, the second one
Answer: 5.43x10^23 g/mole M&M's
Explanation:
1 bag of M&M's = 1.75oz (1.75oz)*(453.6g/16oz) = 49.61 g
1 bag = 55 M&M's
(49.61 g)/55 M&M = 0.9021 g/MM
1 mole M&M's = 6.023x10^23 M&M's
(6.023x10^23 M&M's)*(0.9021 g/MM's) = 5.43x10^23 g/mole molar mass
