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Alik [6]
3 years ago
13

How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0
I think you means the KO2 reacts with H2O. The equation of this reaction is 4KO2+2H2O->4KOH +3O2. The ratio of mole number of O2 and KO2 is 3:4. So the mole number of O2 produced is 0.500/4*3=0.375 mol.
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Since there are 6 C, 5 H, 1 N and 2 O, therefore the total molecular weight is:

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Therefore the molecular weight of nitrobenzene is 123 amu or which is exactly equivalent to 123 g / mol.

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