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Alik [6]
3 years ago
13

How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0
I think you means the KO2 reacts with H2O. The equation of this reaction is 4KO2+2H2O->4KOH +3O2. The ratio of mole number of O2 and KO2 is 3:4. So the mole number of O2 produced is 0.500/4*3=0.375 mol.
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Electron orbitals or shells are also called and abbreviated as?​
umka21 [38]

Answer:

An Orbital is best described as the volume of space in which electrons are most often found

Explanation:

As we know atom consists of sub-particles commonly known as protons, neutrons and electrons. The outer space around the nucleus where the probability of finding electrons is maximum is known as orbital. As the electrons are not precisely ordered around the nucleus hence it is not easy to tell the exact position of an electron.

                Hence, four quantum numbers are used to locate the position of electrons around the nucleus.

  i) Principle Quantum Number:

                                                   This number explains the main energy level which tend to increase in energy as the distance of electrons from nucleus are increased. Principle Quantum Numbers are integer number ranging from one to infinity. Hence, increase in this quantum number results in increase of the size of orbital.

  ii) Azimuthal Quantum Number:

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 iii) Magnetic Quantum Number:

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 iv) Spin Quantum Number:

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6 0
3 years ago
What are the rows of the periodic table called?
Arlecino [84]

Answer:

i believe its called A. periods

4 0
2 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

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3 years ago
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katen-ka-za [31]
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Using GRIGNARDS REAGENT convert methane to ethanol
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Answer:

J

Explanation:

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