Au2S is =<u><em> 426 g/mol</em></u> for molar mass
NaOH + HBr =⇒ NaBr + H2O
35.0 ml HBr x 1 liter/1000 mL x 0.140 moles HBr/ liter = 0.0049 moles HBr
0.0049 moles HBr x 1mole NaOH/1mole HBr = 0.0049 moles HBr
0.0049 moles HBr x 1 liter NaOH/0.200 moles NaOH x 1000 mL/1liter= 24.5 mL NaOH
Answer:- 23.0 mg
Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:
where, 
is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.
From given information, Original amount, of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days
Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:
where, 
is the symbol for half life. let's plug in the value of half like to calculate k:
Let's plug in the values in the first order kinetics equation and solve it for N:
lnN = 3.136
N = 23.0 mg
So, 23.0 mg of Bi-210 would be remaining after 15 days.
Answer:
Spina bifida is a condition that affects the spine and is usually apparent at birth. It is a type of Neural Tube Defect (NTD).
Answer:
The volume increases by 100%.
Explanation:
<u>Step 1:</u> Data given
Number of moles ideal gas = 1 mol
Initial temperature = 305 K
Final temperature = 32°C + 273.15 = 305.15 K
Initial pressure = 2 atm
final pressure = 101 kPa = 0.996792 atm
R = gasconstant = doesn't change
V1 = initial volume
V2= the final volume
<u>Step 2: </u>Calculate volume of original gas
P*V = n*R*T
(P*V)/ T = constante
(P1 * V1) / T1 = (P2 * V2)/ T2
In this situation we have:
(2atm * V1)/ 305 = (0.996792 *V2) / 305.15
0.006557*V1 = 0.003266*V2
V2 = 2*V1
We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.
