Ask question

Ask question

All categories

2 years ago

7

Larissa is writing a coordinate proof to show that the diagonals of a square are perpendicular to each other. She starts by assi

gning coordinates as given.

1 answer:

Llana [10]2 years ago

4 0

The slope of KH is 1

The slope of GJ is -1

The product of the slopes of the diagonals is -1

Therefore, KH is perpendicular to GJ

You might be interested in

What type of triangle, if any, can be formed with sides measuring 8 inches, 8 inches, and 3 inches?

MissTica

We can form an Isosceles triangle using the given measures. Step-by-step explanation: We are given the measure of three sides of a triangle.

5 0

3 years ago

Why all integers are not whole numbers?

gayaneshka [121]

Answer:

Integers -4, -3, -2, -1, 0, 1, 2, 3, 4… all the whole numbers and their opposites (the positive whole numbers, the negative whole numbers, and zero). Fractions and decimals are not integers. For example, -5 is an integer but not a whole number or a natural number.

7 0

3 years ago

Please anyone solve this for me..No spam.

Tamiku [17]

Answer:

3096

Step-by-step explanation:

<u>Given:</u>

$3x-\frac{1}{4y}=24$

<u>Rewrite it as:</u>

$3x=\frac{1}{4y}+24$
$x=\frac{1}{12y}+8$

<u>Simplify the expression:</u>

$8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =$
$8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 3x =$
$8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 24 + \frac{1}{4y} =$
$8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2} + 24 =$
$8(384-\frac{1}{24y^2}) + \frac{1}{3y^2} + 24 =$
$8*384-\frac{1}{3y^2} + \frac{1}{3y^2} + 24 =$
$3072+24=$
$3096$

3 0

2 years ago

A bag contains pennies, nickles, dimes, and quarters.There are 50 coins in all. Of the coins, 10% are pennies and 32% are dimes.

ikadub [295]

10 pennies, 16 dimes, 19 nickles.
Sorry I'm not from US so I don't know your currency. Sorry about that. Hope what I have given you is enough. :)

8 0

2 years ago

In ΔQRS, q = 1.3 inches, r = 1.6 inches and ∠S=157°. Find the length of s, to the nearest 10th of an inch.

hjlf

Answer:

2.8

Step-by-step explanation:

using cosine rule

$s^{2}$ = $1.3^{2} + 1.6^{2} - 2(1.3)(1.6)cos 157$

s = $\sqrt{8.0793}$ = 2.842 = 2.8

8 0

3 years ago