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Varvara68 [4.7K]
2 years ago
9

1•(-1)•1•(-1)-1 Please help!!

Mathematics
2 answers:
DochEvi [55]2 years ago
8 0
Step by step, we have:
1 • (-1)= -1
Then -1 • 1 = -1 and -1 • (-1)= 1 =》 1 - 1 = 0
The answers is 0
Ann [662]2 years ago
6 0

Answer:

the answer is 0

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A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the
nadya68 [22]

Yah same im also an RSM student. 8th Honors?

7 0
3 years ago
Which multiplication expression is eqeul to 3/5 ÷ 1/2
eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

1 \frac{1}{5}

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

1 \frac{1}{5}

So option a = 3/5 x 2/1 is ur answer

8 0
2 years ago
Read 2 more answers
Ryan and Sarah collect baseball cards. Ryan has 150 baseball cards and collects 10 cards per week. Sarah has 200 baseball cards
Nadusha1986 [10]

Answer:

<h2>10 weeks </h2>

Step-by-step explanation:

Step one:

given data

Ryan

number of baseball cards=150

number collected per week= 10

let the number of weeks be x

and the total be y

y=10x+150-----------------1

Sarah

number of baseball cards=200

number collected per week= 5

let the number of weeks be x

and the total be y

y=5x+200------------2

Step two:

Required

the number of weeks where both total will be the same

10x+150=5x+200

10x-5x=200-150

5x=50

divide both sides by 5

x=50/5

x=10 weeks

3 0
2 years ago
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
Once simplified, which of the expressions below is equal to 2x+8? Select all that apply.
romanna [79]

Answer: B) 2(x+4)

Step-by-step explanation: Hope this help :D

5 0
2 years ago
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