Answer:
No. Because it would correspond to zero Instantaneous acceleration.
Explanation:
hope this helps
Answer:
Air resistance slows down the ball
In space, there would be no air resistance
Explanation:
When an object moves through the air, there is a force acting in the opposite direction to the motion of the ball: this force is called air resistance.
Air resistance is due to the friction between the molecules of air and the molecules at the surface of the object - because of this frictional force, the object is slows down in its motion and loses some energy (which is converted into thermal energy of the surrounding air).
There is also the force of gravity (downward) that acts on the ball: however, this force does not slows down the ball in its motion, instead it accelerates it towards the ground.
In space, however, there is no air and no gravity. This means that there are no forces acting on the ball: therefore, the ball will not be slowed down, and therefore will continue its motion forever, at constant velocity, according to Newton's first law:
<em>An object at rest (or in motion) will stay at rest (or in motion at constant velocity) when the net external force acting on it is zero</em>
d = distance the bowling ball has fallen = ?
g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²
t = time of fall for the ball = 3.0 s
distance the ball has fallen is given as
d = (0.5) g t²
inserting the above values in the equation above
d = (0.5) (9.8 m/s²) (3.0 s)²
d = (0.5) (9.8 m/s²) (9.0 s²)
d = (4.9 m/s²) (9.0 s²)
d = 44.1 m
hence the distance fallen by the ball comes out to be 44.1 m
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × 
/ ( 250 × π × 20 )
1300 × 
= (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 × 
so elastic partial width is 2.49 eV
Firstly let us get the time down to minutes from hours. Then the calculation will become easy.
1 hour and 45 minutes = (60 + 45) minutes
= 105 minutes
So
The distance traveled by the car in 105 minutes = 98 miles
Then
The distance traveled by the car in 60 minutes = (98/105) * 60 miles
= 5880/105 miles
= 56 miles
So the average speed of the car as can be seen from the above deduction is 56 miles per hour.
