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Harrizon [31]
3 years ago
10

Lithium was one of the metals studied by the American physicist Robert Millikan in his research on the photoelectric effect. Whe

n illuminated with blue light of frequency 6.64 × 10 14 Hz, the photoelectrons ejected from a lithium surface have a maximum kinetic energy of 0.332 eV. What is the threshold frequency for lithium? For this problem, let the value of Planck's constant, h, be 6.63 × 10 -34 J·s.
Physics
1 answer:
serg [7]3 years ago
3 0

Answer:

Explanation:the answer is 10

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A vertical wire carries a current straight down. To the east of this wire, the magnetic field points: A) toward the east. B) tow
geniusboy [140]

Answer:

option E

Explanation:

the correct answer is option E

the direction of magnetic field will be found out with the help of right hand rule.

Put you palm in the direction of electric field and curl your finger in the direction of magnetic field which east direction.

 now, the direction shown by the thumb will be the direction of magnetic field  which comes out to be toward South direction.

6 0
3 years ago
Read 2 more answers
What are the frequencies of EM spectrum
kap26 [50]

The EM spectrum has no limits.  Any frequency you can imagine
is the frequency of some electromagnetic radiation somewhere.


3 0
3 years ago
in a one dimensional collision, a 4kg object and 6 kg onject have initial velocity. calculate the magnitude of impulse
Greeley [361]

in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18

given,

mass 1 = 4kg

mass 2 = 6kg

velocity 1 = 5ms^1

velocity 2 = 2ms^1

impulse 1 = 4*(5-2)

= 12

Impulse 2 = 6*(5-2)

= 18

Learn more about impulse here

brainly.com/question/16980676

#SPJ4

8 0
1 year ago
A current of 5 A is flowing in a 20 mH inductor. The energy stored in the magnetic field of this inductor is:_______
Kipish [7]

Answer:

C. 0.25J

Explanation:

Energy stored in the magnetic field of the inductor is expressed as E = 1/2LI² where;

L is the inductance

I is the current flowing in the inductor

Given parameters

L = 20mH = 20×10^-3H

I = 5A

Required

Energy stored in the magnetic field.

E = 1/2 × 20×10^-3 × 5²

E = 1/2 × 20×10^-3 × 25

E = 10×10^-3 × 25

E = 0.01 × 25

E = 0.25Joules.

Hence the energy stored in the magnetic field of this inductor is 0.25Joules

7 0
3 years ago
Help with question 16 and 17
storchak [24]
<h3>16.</h3>

Your answer is correct.

___

<h3>17.</h3>

The fractional change in resistance is equal to the given temperature coefficient multiplied by the change in temperature.

  R = R₀×(1 + α×ΔT)

  R = (10.0 Ω)×(1 + 0.004×(65 -20)) = 11.8 Ω

5 0
3 years ago
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