Answer:
The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²
Explanation:
From the question, the given values are as follows:
Initial velocity, u = 90 m/s
final velocity, v = 0 m/s
distance, s = 110 m
acceleration, a = ?
Using the equation of motion, v² = u² + 2as
(90)² + 2 * 110 * a = 0
8100 + 220a = 0
220a = -8100
a = -8100/220
a = -36.81 m/s²
The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²
Answer is 12 milesBecause yeah
Answer:
"Non-uniform velocity" occurs when<em> an object changes its velocity </em>upon motion. This happens when the object either accelerates or decelerates <em>(negative acceleration)</em> in its speed or changes its direction.
Explanation:
"Velocity" refers to<em> speed with a specific direction. </em>
If the velocity is uniform, there's<u> no change in speed and direction</u>. However, if changes occur on either the speed, direction or both, then <em>the velocity becomes </em><u><em>variable or non-uniform.</em></u>
For example, when it comes to a moving car, it is said to be in non-uniform velocity if <em>the distances covered is unequal in relation to the equal intervals of time.</em>
Answer : The change in enthalpy of the reaction is, -310 kJ
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main reaction is,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :
(1) 
(2) 
(3) 
The expression for enthalpy of formation of 
will be,
Therefore, the change in enthalpy of the reaction is, -310 kJ
The answer is Newton's 3rd Law. The reason why is because a force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject ofNewton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.
