Basically the cheetah is running 31.5km/h faster than the gazelle. So to determone how long it will take to cover 9mm at that speed, you have to a lot of work. If you skip all of that work, the answer is 1.60m seconds
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
Answer:
V4=9.197v
Explanation:
Given:
V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms
V4= I4R4 = V2/(R4 + R5)×R4
V4= 12×125 /(125 + 58)
V4=1500/183 =9.197v
Thermal conductions
K= QL/ART
Aluminium T₁ = 10 + 273.15
T₂ = 283.15k
205 = 2.0 × 0.30/4× 10⁻⁴ × (T₂ - 283.15)
Copper
385 = Q × 0.70/4×10⁻⁴ ×(433.15 - T₂)
Where T₃ = 160 + 273.15
T₃ = 433.15K
From 2 to 3
205/385 = 0.30/0.70 × 433.15 - T₂/T₂ - 283.15
= 0.53T₂ -150.06 = 181.92 - 0.42 T₂
→ 0.95T₂ = 331.98 ⇒ T₂ = ₂349.45k
T₂ = 76.3°c
=77°c.
Answer:0.0704 kg
Explanation:
Given
initial Absolute pressure
=210+101.325=311.325
as the volume remains constant therefore
therefore Gauge pressure is 337.44-101.325=236.117 KPa
Initial mass 
Final mass 
Therefore 
=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back
