Answer:
Step-by-step explanation:
Assuming a mean of $204 per night and a deviation of $55.
a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean"
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the cost per night at the hotel, and for this case we know the distribution for X is given by:
Where and
And let represent the sample mean, the distribution for the sample mean is given by:
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability on this way:
We basically have to cancel values on both sides until they are both on common ground.
7 + 3x = 5x + 13
-7 from both sides...
3x = 5x + 6
-5x from both sides...
-2x = 6
/-2 from both sides...
x = -3
Hope this helps!
Answer:
5s⁷/6
s⁵
3r⁴s⁵
-r⁴s⁶
-6rs⁵
4r/5⁶ can't be the first term.
We start with the highest degree term
Answer:
4400
Step-by-step explanation:
134/67 = 2
1100(2)² = 4400