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4 years ago

Identify the precipitate (if any) that forms when KOH and Cu(NO3)2 are mixed

1 answer:

3 0

When KOH and Cu(NO3)2 are mixed it yields copper(II) hydroxide and potassium nitrate. The balanced reaction is:

Cu(No3)2(aq) + 2 KOH(aq)<span> = Cu(OH)2(s) + 2 KNo3(aq)
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As we can see from the equation a solid is formed therefore a precipitate is formed which is the copper (II) hydroxide which has a blue to purple appearance. This can be observed since copper (II) hydroxide has a low solubility in aqueous solution.

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3 years ago

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Afina-wow [57]

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Explanation :

First we have to calculate the mole of $PbCrO_4$ .

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Now we have to calculate the moles of $PbSO_4$ .

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$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

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$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

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3 years ago

Which of the following correctly describes the decomposition of aqueous NaNO3?

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4 years ago

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The correct answer is C) 8.0 D)-13

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