1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slavikrds [6]
3 years ago
5

In which structure does photosynthesis occur?

Chemistry
2 answers:
zhenek [66]3 years ago
8 0

Answer:

b

Explanation:

kloroplast

Degger [83]3 years ago
4 0

Answer:

B. chloroplast

You might be interested in
Why are teeth not minerals?
lozanna [386]
Because your Teeth are composed of calcium, phosphorus, and other minerals. ... But bones are still not as strong as teeth. The hardest part of the human body ,teeth mostly consist of a calcified tissue called dentine. The tooth's dentine tissue is covered in enamel, that hard, shiny layer that you brush.


7 0
3 years ago
Read 2 more answers
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
son4ous [18]

Answer:

F = MA

500 = 50 multiply by A

A= 500/50

A= 10m/s2

3 0
3 years ago
above shows a balloon full of gas which has a volume of 120.0ml at 300.0k assuming pressure remains constant , what is the voume
trasher [3.6K]

128 ml  is the voume of the balloon if the temperature of the gas increases to 320.0k.

Explanation:

given that:

T1 (initial temperature) = 300K

V1 ( initial volume) =  120ml

T2 (final temperature) = 320 K

V2 (final volume) = ?

Pressure remained constant throughout the process.

From the equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Since pressure is constant the equation will be:

\frac{V1}{T1} = \frac{V2}{T2}

V2 = \frac{V1 X T2}{T1}

    Putting the values in the above formula:

V2 = \frac{120 X 320}{300}

     = 128 ml

128 ml is the volume of the gas if temperature increases from 3OO K to 320k

4 0
3 years ago
which of the following statements correctly describes the relative masses of the particles in atoms ​
zysi [14]

Answer:

protons and neutrons

Explanation:

protons and neutrons is equal to mass number

6 0
3 years ago
The half-life of sr-90 is 28 years. after 56 years of decay only 0. 40 g of a sample remains. what was the mass of the original
Svetradugi [14.3K]

Half-life is the time taken for the concentration of the substance to reduce by 50%. The original sample of strontium had a mass of 1.6 gms. Thus, option d is correct.

<h3>What is half-life?</h3>

The half-life of any radioactive substance is the time period at which the concentration will get reduced to half the initial amount. The initial mass of Sr-90 is calculated as,

N(t) = N_{0} (\dfrac{1}{2})^{ \frac{t }{t 1/2}}

Given,

Quantity of the remaining substance N (t) = 0.40 gm

Initial radioactive substance quantity N_{0} =?

Time duration (t) = 56 years

Half-life = 28 years

Substituting values above:

\begin{aligned} 0.40 &= N_{0} (\dfrac{1}{2}) ^{{\frac{56}{28}}\\\\0.40 &= N_{0} (\dfrac{1}{2})^{2}\end{aligned}

= 1.6 gm

Therefore, option d. the initial mass of Sr is 1.6 gm.

Learn more about half-life here:

brainly.com/question/16145921

#SPJ4

7 0
2 years ago
Other questions:
  • What is the molar mass of C4H10
    9·1 answer
  • Which statement concerning elements is true
    10·1 answer
  • Be sure to answer all parts. Nitrogen dioxide decomposes according to the reaction 2 NO2(g) ⇌ 2 NO(g) + O2(g) where Kp = 4.48 ×
    12·1 answer
  • The amount of matter in an object is its
    14·1 answer
  • . Fan blades would be an analogy for which atomic model?
    10·2 answers
  • PPPLLLSSS HELP NOW 15 POINTS WHOEVER ANSWERS
    14·1 answer
  • NEED ASAP!! WILL GIVE BRAINLIEST!! Only have 10 minutes left please help.
    6·1 answer
  • How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution
    15·1 answer
  • True or false. for all atoms of the same element the 4s orbital is larger than the 3s orbital
    13·1 answer
  • Which type of circuit has a string of lights and one light goes out but the others stay lit
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!