Answer:
a. in pure water Solubility (x) = 1.26 x 10⁻⁴M
b. in 0.202M M⁺² Solubility (x) = 9.963 x 10⁻¹²M
The large drop in solubility is consistent with the common ion effect.
Explanation:
a. Solubility in pure water
Given: M(OH)₂ ⇄ M⁺² + 2OH⁻
I --- 0 0
C --- x 2x
E --- x 2x
Ksp = [M⁺²][OH⁻]² = (x)(2x)² = 4x³ => x = CubeRt(Ksp/4)
solubility in pure water = x = CubeRt(8.05 x 10⁻¹²/4) = 1.26 x 10⁻⁴M
b. Solubility in presence of 0.202M M⁺² as common ion.
Given: M(OH)₂ ⇄ M⁺² + 2OH⁻
I --- 0.202M 0
C --- +x +2x
E --- 0.202M + x 2x
≈ 0.202M
Ksp = [M⁺²][2x]² = (0.202)(2x)² = (0.202)(4x²) = 8.05 x 10⁻¹²
=> x = (8.05 x 10⁻¹²)/(0.202)(4) = 9.963 x 10⁻¹²M
Excited state , as stated in quantum mechanics
Answer:
4.5 moles of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C2H5OH + 3O2 —> 2CO2 + 3H2O
From the balanced equation above,
1 moles of C2H5OH reacted to produce 3 moles of H2O.
Finally, we shall determine the number of mole of H2O produced by the reaction of 1.5 moles of C2H5OH. This can be obtained as follow:
From the balanced equation above,
1 moles of C2H5OH reacted to produce 3 moles of H2O.
Therefore, 1.5 moles of C2H5OH will react to produce = 1.5 × 3/ 1 = 4.5 moles of H2O.
Thus, 4.5 moles of H2O will be produced.
Answer:
Combination or synthesis reaction
Explanation:
The reaction is a combination or synthesis reaction.
Let us write the reaction equation:
CO + H₂O → H₂CO₃
A combination or synthesis reaction is one in which a single product forms from two or more reactants. The formation of a compounds from the union of their constituent elements falls into this category of reaction.
- The combination of carbon monoxide and water to give hydrogen carbonate is one of such reaction.
Answer:
<h3>I think, answer is threshold energy.</h3>
OR
<h3>activation energy. </h3>
Explanation:
<h3>Hope it helps you....</h3>
<h2>Thank you..</h2>
