Question

How many x-intercepts appear on the graph of this polynomial function?

Answer 1

Answer:

The correct answer is B.

When you factor the polynomial you get the following:

f(x) = (x^2 + 1)(x)(x - 1)

The last two parenthesis give you the intercepts of 0 and 1. The first parenthesis will give you two non-real zeros, but these are not visible in a graph as the question asks.

Step-by-step explanation:

Answer 2

Answer:  2

Step-by-step explanation:

x⁴ - x³ + x² - x

Factor to find the zeros:

   x³(x - 1) + x(x - 1)

= (x³ + x)(x - 1)

= x(x² + 1)(x - 1)

Zeros are: x = 0,   x = ±i,   x = 1

There are two real zeros and two imaginary zeros.

The x-intercepts are the two real zeros: at x = 0 and x = 1