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3 years ago

NO MFKN LINK

Physics

2 answers:

Gnom [1K]3 years ago

7 0

Answer:

The answer is A

Explanation:

Velocity is the rate of change of its position with respect to a frame of reference, and is a function of time.

Mandarinka [93]3 years ago

6 0

Speed is the answer

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A 25-foot ladder is leaning against a house. The base of the ladder is pulled away from the house at a rate of 2 feet per second

grandymaker [24]

A ladder 25 feet long is leaning against a house. The base of the ladder is pulled away at a rate of 2 ft/sec.

a.) How fast is the top of the ladder moving down the wall when the base of the ladder is 12 feet from the wall?

Answer:

dy/dt = -1.094ft/sec

Explanation:

Given that:

dz/dt = 0,

dx/dt = 2,

dy/dt = ?

Hence, we have the following

Using Pythagoras theorem

We have 25ft as the hypotenuse, y as the opposite or height of wall, and x as the base of the triangle

X² + y² = z²,

12² + y² = 25²,

y² = 25² - 12²

y = √481

Therefore, we have the following:

2x dx/dt + 2y dy/dt,

= 2z dz/dt,

= 12 (2) √481 dy/dt,

= √481 dy/dt = -24,

= dy/dt = -1.094ft/sec

Therefore, final answer is -1.094ft/sec

4 0

3 years ago

The products of one turn of dark reaction cycle are called

harina [27]

Light Independent Reactions

5 0

3 years ago

Like the filters falling through the air, a car on the freeway represents an object with a high Reynolds number traveling throug

Goshia [24]

Answer:

ΔF=125.22 %

Explanation:

We know that drag force on the car given as

$F_D=\dfrac{1}{2}\rho C_DA v^2$

$C_D$ =Drag coefficient

A=Projected area

v=Velocity

ρ=Density

All other quantity are constant so we can say that drag force and velocity can be given as

$\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}$

Now by putting the values

$\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}$

$\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}$

$\dfrac{F_D_1}{F_D_2}=0.444$

Percentage Change in the drag force

$\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100$

$\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100$

$\Delta F=\dfrac{1-0.444}{0.444}\times 100$

ΔF=125.22 %

Therefore force will increase by 125.22 %.

3 0

3 years ago

A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consu

timurjin [86]

The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

The given parameters:

Number of light bulbs = 10
Power consumed by each bulb = 100 W
Time of energy consumption, t = 1 year

<h3>What is electrical energy?</h3>

This is the electric power consumed or dissipated at a given period of time.

The electrical energy consumed in one year by using the light bulbs is calculated as

E = Pt

$E = (100 \times 10) \times (1 \ yr \times \frac{8760 \ hrs}{1 \ yr} )= 8,760,000 \ W att-hours\\\\
E = \frac{8,760,000 }{1000} = 8,760 \ kWh$

Thus, the electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

Learn more about electrical energy here: brainly.com/question/60890

4 0

2 years ago

The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?

larisa86 [58]

Answer:

$(a)255mm \\ (b)0.255m$

Explanation:

$(a)1cm = 10mm \\ 25.5cm = x$

Cross multiply

$1x = 25.5 \times 10 \\ x = 255mm$

$(b)100cm = 1m \\ 25.5cm = x$

cross multiply

$100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m$

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0

4 years ago

Read 2 more answers