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3 years ago

5

If a 51kg snowboarder falls of a cliff, and is falling 15 m/s when they impact the snow, what is the average force of the snow o

n them if they came to a stop in 0.56 seconds? Answer in Newton’s

1 answer:

storchak [24]3 years ago

5 0

Answer:

Average force is F = mass times change in V/ change in time so..

1 366.07143 N

Explanation:

51 kg x 15 m/s / 0.56

1 366.07143 m kg / s

1 366.07143 N

1 kilogram 1 meter per second per second = 1 N

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wo parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area o

tresset_1 [31]

Complete Question

Two parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area of 5.30 cm2 and plate separation of 2.65 mm. However, the first capacitor C1 is filled with air, while the second capacitor C2 is filled with a dielectric that has a dielectric constant of 2.10.

(a) What is the charge stored on each capacitor

(b) What is the total charge stored in the parallel combination?

Answer:

a

i $Q_1 = 2.124 *10^{-11} \ C$

ii $Q_2 = 4.4604 *10^{-11} \ C$

b

$Q_{eq} = 6.5844 *10^{-11} \ C$

Explanation:

From the question we are told that

The voltage of the battery is $V = 12.0 \ V$

The plate area of each capacitor is $A = 5.30 \ cm^2 = 5.30 *10^{-4} \ m^2$

The separation between the plates is $d = 2.65 \ mm = 2.65 *10^{-3} \ m$

The permittivity of free space has a value $\epsilon_o = 8.85 *10^{-12} \ F/m$

The dielectric constant of the other material is $z = 2.10$

The capacitance of the first capacitor is mathematically represented as

$C_1 = \frac{\epsilon * A }{d }$

substituting values

$C_1 = \frac{8.85 *10^{-12 } * 5.30 *10^{-4} }{2.65 *10^{-3} }$

$C_1 = 1.77 *10^{-12} \ F$

The charge stored in the first capacitor is

$Q_1 = C_1 * V$

substituting values

$Q_1 = 1.77 *10^{-12} * 12$

$Q_1 = 2.124 *10^{-11} \ C$

The capacitance of the second capacitor is mathematically represented as

$C_2 = \frac{ z * \epsilon * A }{d }$

substituting values

$C_1 = \frac{ 2.10 *8.85 *10^{-12 } * 5.30 *10^{-4} }{2.65 *10^{-3} }$

$C_1 = 3.717 *10^{-12} \ F$

The charge stored in the second capacitor is

$Q_2 = C_2 * V$

substituting values

$Q_2 = 3.717*10^{-12} * 12$

$Q_2 = 4.4604 *10^{-11} \ C$

Now the total charge stored in the parallel combination is mathematically represented as

$Q_{eq} = Q_1 + Q_2$

substituting values

$Q_{eq} = 4.4604 *10^{-11} + 2.124*10^{-11}$

$Q_{eq} = 6.5844 *10^{-11} \ C$

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4 years ago

Nataly_w [17]

A is the answer i hope

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4 years ago

A room with translucent windows that include some colored parts. use the drop-down menus the complete the statements about the i

Umnica [9.8K]

(a)The window panes are transparent

(b)The colors of the panes are due to the wavelengths of light that the glass allows to pass through.

<h3>What are trasparent glasses?</h3>

The glasses which allows the light rays to pass through them are called as the transparent glasses.

or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that is perceived by the human eye.[1] Visible light is usually defined as having wavelengths in the range of 400–700 nanometres (nm),

corresponding to frequencies of 750-420 terahertz, between the infrared (with longer wavelengths) and the ultraviolet (with shorter wavelengths

Hence the window panes are transparent the colors of the panes are due to the wavelengths of light that the glass allows to pass through.

To know more about trasparent glasses follow

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3 years ago

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9. A weather satellite is launched from the ground and placed in orbit six times farther away from the earth's centre. The gravi

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Answer: d

One thirty-sixth of

Explanation: Gravitational field or gravitational field strength obeys the inverse square law. The gravitational field is inversely proportional to the square of the earth distance. That is,

g = Gm/r^2

Where r = distance.

If weather satellite is placed in orbit six times farther away from the earth's centre, gravitational field will be one thirty-sixth of its initial value.

Therefore, the gravitational field experienced by the satellite in orbit is one thirty-sixth of the field that it experienced on the ground.

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3 years ago

a car is travelling down the road at 25m/s. its mass is 1000kg. what net external force is necessary to bring the car to a stop

maxonik [38]

Answer:

ans: 2.5 × 10^ 4 Newton

Explanation:

do as above shown ; thank you

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3 years ago