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3 years ago

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The three particles that make up atoms are Question 9 options: protons, neutrons, and isotopes. positives, negatives, and neutra

ls. protons, neutrons, and electrons. neutrons, isotopes, and electrons.

1 answer:

serious [3.7K]3 years ago

3 0

Answer: protons , neutrons and electrons

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Something is thrown in the air and 5.35 seconds later it lands on something 2.1 meters from the ground. How fast was it thrown u

UNO [17]

Answer:

26.6 m/s

Explanation:

Given:

Δy = 2.1 m

t = 5.35 s

a = -9.8 m/s²

Find: v₀

Δy = v₀ t + ½ at²

(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²

v₀ = 26.6 m/s

5 0

3 years ago

Derive the following equations of motion

xz_007 [3.2K]

Answer:

___________________________________

<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

$a = \frac{v - u}{t} \\ or \: at = v - u \\ v = u + at \:$

It is first equation of motion.

___________________________________

<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

$v = u + at...........(i) \\ s = \frac{u + v}{2} \times t.........(ii)$

Putting the value of v from the equation (i) in equation (ii), we have,

$s= \frac{u + (u + at)}{2} \times t \: \: \\ or \: s = \frac{(2u + at)t}{2} \\ or \: s = \frac{2ut + a {t}^{2} }{2} \\ s = ut + \frac{1}{2} a {t}^{2}$

It is third equation of motion.

________________________________

<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

$v = u + at.....(i) \\ s = \frac{u + v}{2} \times t......(ii) \\$

$v = u + at \\ or \: at = v - u \\ t = \frac{v - u}{a}$

Putting the value of t from (i) in the equation (ii)

$s = \frac{u + v}{2} \times \frac{v - u}{a} \\ or \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ or \: 2as = {v}^{2} - {u}^{2} \\ {v}^{2} = {u}^{2} + 2as$

It is forth equation of motion.

________________________________

Hope this helps...

Good luck on your assignment..

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