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3 years ago

What is happening to this graph when the x-values are between 4 and 8?

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

Answer: it remains constant

Step-by-step explanation: because between 4 and 8 there is no change

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You construct lines p, q, r, and s such that p || q, r ⊥ p, and s ⊥ q. Which of the following must be true?

jolli1 [7]

Answer:

r ll s

Step-by-step explanation:

The easiest way to solve thi is to draw a picture .

P and Q are parallel, so draw those as two opposite seides of a square.

R and P are perpendictular so draw that as the top line of the square. Since it is perpendicular to P, R has to be perpendictular to Q.

Draw line S as the bottom line of the square and the same rules apply, so R is parallel to S

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3 years ago

Help me plz math (picture)

skad [1K]

For 34, since each diameter is in scientific notation , meaning that we have one number (1-9) followed by a decimal, we simply see which has the smallest power, which is cell C.

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3 years ago

Ava wrote the expression StartFraction 4 minus 2 Over 3 minus 1 EndFraction to determine the slope of a line. Which table might

Katena32 [7]

Answer:

The question is not finished but if it is it would look like 4-2/3-1

Step-by-step explanation:

3 0

3 years ago

What do I have to put

saw5 [17]

Answer: for question 1, i think you have to put yes because absolute value is always positive so it´s 6.5 and the opposite of -6.5 is 6.5

Step-by-step explanation:

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3 years ago

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s

wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0

3 years ago