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Afina-wow [57]
3 years ago
8

What is the present value of $9,000 paid at the end of each of the next 86 years if the interest rate is 10% per​ year? the pres

ent value is ​$ -?
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

It will be $900

Hope it helps!

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The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
The nurse is conducting a postparum examination on a client who reports pain and is unable to sit comfortably. The perineal exam
djverab [1.8K]

Answer:

d. place an ice pack

Step-by-step explanation:

5 0
3 years ago
For this question I am sure the answer is 81% as you divide 45 and 55. However, it is stating my answer is incorrect even though
77julia77 [94]

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

8 0
2 years ago
A hiker averages 3/8 kilometers per hour. If he hikes for 1/3 hours, how many kilometers does he hike?
balandron [24]

Answer: 1/8 km

Step-by-step explanation:

3/8 * 1/3 = 1/8

5 0
3 years ago
Can someone help me and show the work pls.
Ivan

(1 & 2/3) ft = (1 ft) + (2/3 ft)

(1 & 2/3) ft = 12 inches + 12*(2/3) inches

(1 & 2/3) ft = 12 inches + 8 inches

(1 & 2/3) ft = 20 inches

If the tree grows 5 inches per year, then it will take 4 years to get to 20 inches since 5*4 = 20. You can also divide to get 20/5 = 4.

So it takes 4 years for the tree to grow 1&2/3 feet tall.

8 0
3 years ago
Read 2 more answers
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