HC]A laboratory experiment requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M
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Answer : The pH of the solution is, 3.41
Explanation :
First we have to calculate the moles of .
Now we have to calculate the value of .
The expression used for the calculation of is,
Now put the value of in this expression, we get:
The reaction will be:
Initial moles 0.375 0.100 0.375
At eqm. (0.375-0.100) 0 (0.375+0.100)
= 0.275 = 0.475
Now we have to calculate the pH of solution.
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
Thus, the pH of the solution is, 3.41