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puteri [66]
2 years ago
12

Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.

Physics
1 answer:
shusha [124]2 years ago
5 0

The destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

<h3>What is the definition of destructive interference?</h3>

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

\rm d sin \theta = n \lambda

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by \rm \lambda.

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

To learn more about destructive interference refer to the link;

brainly.com/question/16098226

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Answer:

5.38 m/s^2

Explanation:

NET force causing the object to accelerate  =  50 -10 = 40 N

Mass of the object =  73 N / 9.81 m/s^2 = 7.44 kg

F = ma

40 = 7.44 * a         a = 5.38 m/s^2

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1 year ago
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luda_lava [24]

100m: 4.9 kJ

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8 0
2 years ago
to start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 53.0° above the ho
kap26 [50]
So this is easy to calculate when you split the velocity into x and y components. The x component is going to equal cos(53) * 290 and the y component is going to equal sin(53)*290.

The x location therefore is 290*cos(53)*35 = 6108.4m

The y location needs to factor in the downwards acceleration of gravity too, which is 9.81m/s^2. We need the equation dist. = V initial*time + 0.5*acceleration*time^2.

This gives us d=290*sin(53)*35 + (0.5*-9.81*35^2)=2097.5m

So your (x,y) coordinates equals (6108.4, 2097.5)
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3 years ago
Light travels at a speed of close to 3 x 10^5 km/s in vacuum. Given that it takes light 8 min and 19 s to travel the distance fr
never [62]

Answer:

1497×10⁵ km

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Speed of light in vacuum = 3×10⁵ km/s

Time taken by the light of the Sun to reach the Earth = 8 min and 19 s

Converting to seconds we get

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Distance = Speed × Time

\text{Distance}=3\times 10^5\times 499\\\Rightarrow \text{Distance}=1497\times 10^5\ km

1 AU = 1497×10⁵ km

The Sun is 1497×10⁵ km from Earth

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3 years ago
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