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3 years ago

Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.

1 answer:

5 0

The destructive interference formula for diffraction grating problems is $d sin \theta = (n+\frac{1}{2})\lambda$ .

<h3>What is the definition of destructive interference?</h3>

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

$\rm d sin \theta = n \lambda$

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by $\rm \lambda$ .

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is $d sin \theta = (n+\frac{1}{2})\lambda$ .

To learn more about destructive interference refer to the link;

brainly.com/question/16098226

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30 minus 3 plus 4 is equal to what

Pepsi [2]

Answer:

Explanation:

quick maths

6 0

3 years ago

Read 2 more answers

A power cycle operates between hot and cold reservoirs at 1200 K and 300 K, respectively. At steady state the cycle develops a p

GenaCL600 [577]

Answer:

Explanation:

a ) Thermal efficiency = work output / heat input

= .38 MW / 1 MW = .38

OR 38%

Heat rejected at cold reservoir = heat input - work output

1 MW - .38 MW

= 0.62 MW.

b ) For reversible power output

efficiency = T₂ - T₁ / T₂ ; T₂ is temperature of hot reservoir and T₁ is temperature of cold reservoir.

= 1200 - 300 / 1200 = 900 / 1200

= .75

or 75%

rate at which heat is rejected

= 1 - .75 x 1

= .25 MW .

7 0

3 years ago

Derive the velocity of an electron in a hydrogen atom using Bohr's model. The electron has a mass of m, charge of (-e) and an or

Ahat [919]

Answer:

$v=\frac{Ze^2}{2 \epsilon_0\times n\times h}$

$v=\frac {2.185\times 10^6}{n}\ m/s$

Explanation:

According to Bohr's Theory,

The force of attraction acting between the electron and the nucleus is equal to the centrifugal force acting on the electron.

Thus,

$\frac{Ze^2}{4\pi \epsilon_0 r^2}=m_e\frac{v^2}{r}$ ......1

Where, Z is the atomic number or the number of protons

r is the atomic radius

v is the velocity of the electron

$m_e$ is the mass of the electron

Also,

Accoriding to Bohr, the angular momentum is quantized. He states that the angular momemtum is equal to the integral multiple of $\frac {h}{2\times \pi}$ .

$m_e vr=n\times \frac {h}{2\times \pi}$ ....2

solving r from equation 2, we get that:

$r=n\times \frac {h}{2\times \pi\times m_e v}$

Putting in 1 , we get that:

$v=\frac{Ze^2}{2 \epsilon_0\times n\times h}$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185\times 10^6}{n}\ m/s$

4 0

4 years ago

Collins body metabolizes caffeine at a rate of 14.3% per hour (so the amount of caffeine in Collins body decreases by 14.3% each

Oksanka [162]

Answer:

It will take 4.5 h to metabolize 50% of the ingested caffeine.

Explanation:

Hi there!

We have to find how long will it take Collin´s body to metabolize 50% (40 g) of the ingested caffeine. We know that Collin´s body metabolizes 14.3 % of the amount of caffeine each hour. Then, every hour the caffeine will be reduced by 14.3 %.

After the first hour, the amount of caffeine will be:

80 - 80 · 0.143 = 68.56

Expressed in other form

80 · (1 - 0.143) = 68.56

80 · 0.857 = 68.56

After the second hour, the amount of caffeine will be:

68.56 - 68.56 · 0.143 = 58.75592

68.56 · 0.857 = 58.75592

Since 68.56 = 80 · 0.857, we could write the amount of caffeine after 2 hours as:

80. 0.857 · 0.857 = 58.75592

After the third hour:

58.75592 - 58.75592 · 0.143 = 50.35382344

58.75592 · 0.857 = 50.35382344

In the same way, since 58.75592 = 80. 0.857 · 0.857 the amount of caffeine after 3 hours will be:

80. 0.857 · 0.857 · 0.857 = 50.35382344

Then after x hours, the amount of caffeine in the body will be:

80 mg · 0.857ˣ

We have to find the value of x for which that expression is equal to 40 mg:

80 mg · 0.857ˣ = 40 mg

0.857ˣ = 40 mg/ 80 mg

0.857ˣ = 0.5

Apply ln to both side of the equation:

ln(0.857ˣ) = ln(0.5)

Apply logarithm property : ln(xᵃ) = a ln(x)

x ln(0.857) = ln(0.5)

x = ln(0.5)/ln(0.857)

x = 4.5 h

It will take 4.5 h to metabolize 50% of the ingested caffeine.

3 0

3 years ago

Calculate the volume of a 5-g sample of pure gold

Bond [772]

Answer:

≈ 0.26 cm³

Explanation:

Hi there !

Gold is a metal with a very high density.

The density of gold is higher than that of lead.

Density(gold) = 19300 kg/m³ = 19.3 g/cm³

19.3 g ............ 1 cm³

5 g ..................x cm³

x = 5g×1cm³/19.3g = 0.2590 cm³ ≈ 0.26 cm³

Good luck !

5 0

4 years ago