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puteri [66]
3 years ago
12

Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.

Physics
1 answer:
shusha [124]3 years ago
5 0

The destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

<h3>What is the definition of destructive interference?</h3>

Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.

The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:

\rm d sin \theta = n \lambda

The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by \rm \lambda.

The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.

Hence the destructive interference formula for diffraction grating problems is d sin \theta = (n+\frac{1}{2})\lambda.

To learn more about destructive interference refer to the link;

brainly.com/question/16098226

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What is the Period Table
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Answer:

Explanation:

Arrangement of all known elements to men based on state of matter reactivity and valence shell structure

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3 years ago
The highest barrier that a projectile can clear is 19.7 m, when the projectile is launched at an angle of 15.0o above the horizo
svlad2 [7]

Answer:

76 m /s

Explanation:

maximum height, H = 19.7 m

Angle of projection, θ = 15 degree

Let u be the projectile launch speed

Use the formula of maximum height

H = u^{2}Sin\theta ^{2}/2g

19.7 = u^{2}Sin^{2}15/19.6

u = 75.9199 = 76 m /s

6 0
3 years ago
What is the gauge pressure (in atm) in a 25.0°C car tire containing 3.81 mol of gas in a 31.5 L volume? (Enter your answer to at
bagirrra123 [75]

Answer:

Explanation:

Given

Temperature of gas T=25^{\circ}C\approx 298\ K

Volume of gas V=31.5\ L\approx 31.5\times 10^{-3}\ m^3

no of moles of gas n=3.81\ mol

Using Ideal gas Equation to find the Pressure of gas

PV=nRT

where P=Absolute Pressure

V=Volume

R=Universal gas constant

T=Temperature

P\times 31.5\times 10^{-3}=3.81\times 8.314\times 298

P=\frac{3.81\times 8.314\times 298}{31.5\times 10^{-3}}

P=299.66\ kPa

And we know Atmospheric Pressure is 101.325\ kPa

Therefore Gauge pressure is given by

P_{gauge}=P-P_{atm}

P_{gauge}=299.66-101.325

P=198.34\ kPa

4 0
3 years ago
I feel like I’ve been on this physics exam forever… please help . NO LINKS.
sesenic [268]

Explanation:

my guess is A

emission spectrum of a chemical element or chemical compound is the spectrum of frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state.

4 0
3 years ago
Help please, last ride guys
Ierofanga [76]

Answer:

Solution ( for fourth attachment ) : 38°C

Tip : Remember the units °C when submitting answer

Explanation:

As you mentioned, we only need the solution for the fourth attachment.

The idea here is that the heat lost by the metal will be equal to the heat gained by the water. We know that the specific heat gained or lost will always be represented by the following formula,

q = m * c

Therefore if we substitute the know values and equate the two equations knowing that " q " is common among them --- ( 1 )

0.33 * 448

Remember that the change in temperature of iron (ΔT) would be represented by final temperature - initial temperature, or final temperature - 693. Similarly the change in temperature of water will be final temperature - 39. Now we can pose the final temperature as a, and solve for a through substitution --- ( 2 )

0.33 * 448

From here on take a look at the attachment. It represents how to receive get a through simple algebra. Here a, the final temperature, is about 38°C. In exact terms it will be 38.03617\dots°C.

6 0
3 years ago
Read 2 more answers
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