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Novay_Z [31]
3 years ago
5

Any four difference between speed and acceleration ​

Physics
1 answer:
Mumz [18]3 years ago
6 0

<u>Speed:</u>

  • Measured in distance / time
  • It tells the speed of a body
  • It is a scalar quantity
  • Speed is always positive
  • It's unit is meter per second

<u>Acceleration:</u>

  • Measured in velocity / time
  • It tells the change in the velocity
  • Implied on change in a velocity
  • It is a vector quantity
  • It's unit is meter per second square

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Write answers with significant figures:<br>a) 17.35 g +8.498 g​
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Answer:

25.9 g

Explanation:

= 17.35

8.498

________+

= 25.848 g = 25.85 g = 25.9 g

*so sorry if wrong

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3 years ago
Who makes the first atomic bomb?​
Svetradugi [14.3K]

Answer:

Robert Oppenheimer made the first atomic bomb.

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3 years ago
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A lighthouse is located on a small island, 3 km away from the nearest point on a straight shoreline, and its light makes four re
lbvjy [14]

Answer:

The beam of light is moving at the peed of:

\frac{dy}{dt} = \frac{80\pi}{3} km/min

Given:

Distance from the isalnd, d = 3 km

No. of revolutions per minute, n = 4

Solution:

Angular velocity, \omega = \frac{d\theta'}{dt} = 2\pi n = 2\pi \times 4 = 8\pi    (1)

Now, in the right angle in the given fig.:

tan\theta' = \frac{y}{3}

Now, differentiating both the sides w.r.t t:

\frac{dtan\theta'}{dt} = \frac{dy}{3dt}

Applying chain rule:

\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}

sec^{2}\theta'\frac{d\theta'}{dt} = \frac{dy}{3dt} = (1 + tan^{2}\theta')\frac{d\theta'}{dt}

Now, using tan\theta = \frac{1}{m} and y = 1 in the above eqn, we get:

(1 + (\frac{1}{3})^{2})\frac{d\theta'}{dt} = \frac{dy}{3dt}

Also, using eqn (1),

8\pi\frac{10}{9})\theta' = \frac{dy}{3dt}

\frac{dy}{dt} = \frac{80\pi}{3}

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3 years ago
Does air resistance affect the motion of a falling object differently when the initial velocity of the object is greater?
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The frequency of the pendulum is independent of the mass on the end. (c)

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3 years ago
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