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storchak [24]
3 years ago
11

How many moles of O2 are needed to make 1.98 moles of SO3

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0
When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
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Draw the diazonium cation formed when cytosine reacts with nano2 in the presence of hcl.
Sindrei [870]
Answer in the Word document below.
Diazonium compounds are a group of organic compounds sharing a common functional group R−N₂⁺. The process of forming diazonium compounds is called diazotation and usually <span>are prepared by treatment of aromatic amines with </span>nitrous acid<span> and additional acid (hydrochloric acid).
</span>Cytosine is one of the four main bases found in DNA and RNA.
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7 0
3 years ago
Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
3 years ago
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I need the answer to 452 of arogon
yaroslaw [1]
I'm confused... is there more info? 
3 0
3 years ago
If the mass of 3 black beans it's 0.7 what's the mass of one bean?
mamaluj [8]

Answer:0.233333333

Explanation: Let me be!

3 0
2 years ago
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A balanced chemical equation is shown below
IrinaVladis [17]

Answer:

The answer is A.

Explanation:

C6H12O6 + 6O2 -> 6CO2 + 6H20

C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)

4 0
3 years ago
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