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4 years ago

How many moles of O2 are needed to make 1.98 moles of SO3

Chemistry

1 answer:

lina2011 [118]4 years ago

4 0

When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.

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3 years ago

Picture a neutral P atom. This neutral atom will have

aleksandr82 [10.1K]

Answer:

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3 years ago

Which of the following units would be the most appropriate for measuring the mass of a grain of rice? A. milligrams B. grams C.

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3 years ago

Read 2 more answers

How many moles are contained 80.3 gram of sm(no3)3

swat32

<h3>Answer:</h3>

0.239 mol Sm(NO₃)₃

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Moles

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[Given] 80.3 g Sm(NO₃)₃

[Solve] moles Sm(NO₃)₃

Step 2: Identify Conversions

[PT] Molar Mass of Sm - 150.36 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 80.3 \ g \ Sm(NO_3)_3(\frac{1 \ mol \ Sm(NO_3)_3}{336.39 \ g \ Sm(NO_3)_3})$
[DA] Divide [Cancel out units]: $\displaystyle 0.238711 \ mol \ Sm(NO_3)_3$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃

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3 years ago

What is the percent by volume of ethanol in the final solution when 45 mL of ethanol is diluted to a volume of 250 mL with water

Readme [11.4K]

Answer:

%Volume of ethanol = 15.25%

Explanation:

Volume of water = 250mL

Volume of ethanol = 45mL

The total volume of the solution = volume of ethanol + volume of water

Total volume = 45 + 250 = 295mL

%Volume of ethanol = Vol. of ethanol / Total volume x 100

%Volume of ethanol = 45/295 x 100

%Volume of ethanol = 15.25%

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3 years ago