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zvonat [6]
4 years ago
5

4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),

what is the new volume?
Chemistry
1 answer:
Elina [12.6K]4 years ago
6 0

Answer : The value of new volume is, 50.0 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure at STP = 1 atm

P_2 = final pressure =  4.00  atm

V_1 = initial volume at STP = 200.0 mL

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

1atm\times 200.0mL=4.00atm\times V_2

V_2=50.0mL

Therefore, the value of new volume is, 50.0 mL

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Answer:

1.12×10¹¹ kg of CO₂ are produced with 4.6×10¹⁰ L of isooctane

Explanation:

Let's state the combustion reaction:

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Let's calculate the mass of isooctane that reacts.

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First of all, let's convert the volume in L to mL, so we can use density.

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3.64 ×10¹³ g . 1mol / 114 g = 3.19×10¹¹ mol

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2.55×10¹² mol . 44 g/mol = 1.12×10¹⁴ g of CO₂

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