4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),
1 answer:
Answer : The value of new volume is, 50.0 mL
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure at STP = 1 atm
= final pressure = 4.00 atm
= initial volume at STP = 200.0 mL
= final volume = ?
Now put all the given values in the above equation, we get:
Therefore, the value of new volume is, 50.0 mL
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Explanation:
- For path A, the calculation will be as follows.
As, for reversible isothermal expansion the formula is as follows.
W =
Since, we are not given the number of moles here. Therefore, we assume the number of moles, n = 1 mol.
As the given data is as follows.
R = 8.314 J/(K mol), T = 298 K ,
= 8.34 L,
= 2.67 L
Now, putting the given values into the above formula as follows.
W =
=
=
= -2818.68 J
Hence, work for path A is -2818.68 J.
- For path B, the calculation will be as follows.
Step 1: When there is no change in volume then W = 0
Hence, for step 1, W = 0
Step 2: As, the gas is allowed to expand against constant external pressure = 1.00 atm.
So, W =
Now, putting the given values into the above formula as follows.
W =
=
= -5.67 atm L
As we known that, 1 atm L = 101.33 J
Hence, work will be calculated as follows.
W =
= -574.54 J
Therefore, total work done by path B = 0 + (-574.54 J)
W = -574.54 J
Hence, work for path B is -574.54 J.
Answer:
Explanation:
To find the density of nitrogen gas at STP which is standard temperature and pressure, certain parameters must be known.
The mass of the gas must be given or its volume.
Density of a substance is the mass per unit area;
Volume of gas at STP = number of moles x 22.4
Using the volume obtained here,
Density =
Then we can find the density.
The mass is very important.