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MatroZZZ [7]
3 years ago
7

The corn crop in an area is prone to infestation by larvae from moths that feed on the cornstalks and ears of corn. The techniqu

es used by two farmers to protect the corn crop are described below.
Technique A: Sprayed his corn crop with an insecticide. The insecticide is known to kill all honeybee, butterfly, and moth larvae.
Technique B: Used a genetically modified variety of corn. The plant produces an insecticide which selectively kills only the moth larvae as it feeds on the corn.
Which technique is likely to have less of an impact on the environment?
Technique B because it preserves the harmless insects and targets only the moth larvae


Technique A because insecticide use is better for preserving the environment

Technique B because it may help humans who consume corn to fight bacA genetically engineered corn plant is approved for agricultural use.

Technique A because it kills a broader variety of insects to protect the corn
Chemistry
2 answers:
Mrac [35]3 years ago
8 0

Answer:

a

Explanation:

lozanna [386]3 years ago
7 0
Pretty sure the answer is A
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A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve
Helen [10]

Answer:

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

Explanation:

The differential equation is given as:

\frac{dC}{dt} = r- kC

\frac{dC}{r- kC} = dt

Taking integral of both sides; we have:

\int\limits  \frac{dC}{r- kC} = \int\limits dt

-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD

r-kC=e^{-kt-kD}

r-kC=e^{-kt}e^{-kD}

r-kC=Ae^{-kt}

kC=r-Ae^{-kt}

C=\frac{r}{k}-\frac{A}{k}e^{-kt}

C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}     ------- equation (1)

If C(0)= C_o ; we have:

C(0)= \frac{r}{k}-\frac{A}{k}e^0         (where; A is an integration constant)

C_o = \frac{r}{k}- \frac{A}{k}

C_o=\frac{r-A}{k}

kC_o=r-A

A=r-kC_o

Substituting A=r-kC_o into equation (1); we have;

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

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