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tatiyna
3 years ago
10

What are some uses for graphite

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0
Because it is a solid material, it is known as a dry lubricant. This is useful inapplications<span> where “wet” lubricants, such as oil, cannot be </span>used<span>. </span>Graphite<span> is the only non-metal element that is a good conductor of electricity. Natural </span>graphite<span> is </span>used <span>mostly in what are called refractory </span><span>applications</span>
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kakasveta [241]

Answer:

Graphitic carbon nitride (g-C3N4) is a rising two-dimensional material possessing intrinsic semiconducting property with unique geometric configuration featuring superimposed heterocyclic sp2 carbon and nitrogen network, nonplanar layer chain structure, and alternating buckling. The inherent porous structure of heptazine-based g-C3N4 features electron-rich sp2 nitrogen, which can be exploited as a stable transition metal coordination site. Multiple metal-functionalized g-C3N4 systems have been reported for versatile applications, but local coordination as well as its electronic structure variation upon incoming metal species is not well understood. Here we present detailed bond coordination of divalent iron (Fe2+) through micropore sites of graphitic carbon nitride and provide both experimental and computational evidence supporting the aforementioned proposition.

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3 years ago
Type the correct answer in the box. Spell all words correctly. In which system are both energy and matter exchanged with the sur
Anna11 [10]

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open system

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4 0
3 years ago
200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?
Ipatiy [6.2K]
  • M be molar concentration
  • V be volume

So

  • M1=0.845M
  • V1=200mL=0.2L
  • V2=0.6L
  • M2=?

\\ \tt\rightarrowtail M1V1=M2V2

\\ \tt\rightarrowtail 0.845(0.2)=0.6M2

\\ \tt\rightarrowtail 0.169=0.6M2

\\ \tt\rightarrowtail M2=0.281M

7 0
2 years ago
A 283.3-g sample of X2(g) has a volume of 30 L at 3.2 atm and 27 'C. What is element X?
professor190 [17]

we find the number of moles with the formula

pV=nRT

27C=300k

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we have the mass ant the number of moles so we can calculate the molar mass

283.3/3.9=72.64g/moles

that means X's mass is 72.64/2=36.3 so the element is Kr(Kriptonium)

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Identify fossil types match each each type of fossil to its description
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Well we need to see the fossil
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3 years ago
Read 2 more answers
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