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tatiyna
3 years ago
10

What are some uses for graphite

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
4 0
Because it is a solid material, it is known as a dry lubricant. This is useful inapplications<span> where “wet” lubricants, such as oil, cannot be </span>used<span>. </span>Graphite<span> is the only non-metal element that is a good conductor of electricity. Natural </span>graphite<span> is </span>used <span>mostly in what are called refractory </span><span>applications</span>
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3 years ago
3. Which plane’s velocity was greatest?
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North American X-15

Explanation:

This is the fastest manned aircraft

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Which law is based on the graph that is shown below? A graph is shown with pressure on the horizontal axis and volume on the ver
DIA [1.3K]

<u>Answer:</u>

"Boyle's Law" is based on the graph that is shown below.

<u>Explanation:</u>

Boyle's law or Boyle – Mariotte law or Mariotte's law, is an experimental gas law that discusses how a gas's pressure tends to rise as the container volume start declining. This shows the relationship between pressure and volume for a fixed mass at a constant temperature, i.e., number of a gas molecules.This rule visualizes the actions of gas molecules in a confined space. This law can be understood from following equation:

p₁V₁ = p₂V₂

Above the product of the initial volume and pressure is equal to the product of the volume and pressure after a change.

5 0
3 years ago
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A 25.225 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 75.815 g of wa
Rudik [331]

Answer:

1.43 (w/w %)

Explanation:

HCl reacts with NH3 as follows:

HCl + NH3 → NH4+ + Cl-

<em>1 mole of HCl reacts per mole of ammonia.</em>

Mass of NH3 is obtained as follows:

<em>Moles HCl:</em>

0.02999L * (0.1068mol / L) = 3.203x10-3 moles HCl = <em>Moles NH3</em>

<em>Mass NH3 in the aliquot:</em>

3.203x10-3 moles NH3 * (17.031g / mol) = 0.0545g.

Mass of sample + water = 22.225g + 75.815g = 98.04g

Dilution factor: 98.04g / 14.842g = 6.6056

That means mass of NH3 in the sample is:

0.0545g * 6.6056 = 0.36g NH3

Weight percent is:

0.36g NH3 / 25.225g * 100

<h3>1.43 (w/w %)</h3>
6 0
3 years ago
Pls help the answers and questions r in the pic
soldier1979 [14.2K]
It would be 9*10 to the -3
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3 years ago
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