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LekaFEV [45]
3 years ago
10

Which state of matter are particles packed tightly together and fix positions

Chemistry
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

Solids.

Explanation:

In a solid object, particles are packed tightly together in fixed positions even if in a container.

olganol [36]3 years ago
5 0

Answer:

solids

Explanation:

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Are metal ions larger or smaller than the neutral atoms they came from
NeX [460]

Answer: the metal ions or smaller then the neutral

Explanation:

7 0
4 years ago
Calculate the volume of 4.00 molar NaOH solution required to prepare 100 mL of a 0.500 molar solution of NaOH.
Kazeer [188]

Answer:

The answer to your question is V₁ = 12.5 ml

Explanation:

Data

Volume = V₁?

[NaOH] = C₁ = 4.0 M

Volume 2 = V₂ = 100 ml

[NaOH] = C₂ = 0.5 M

Formula of dilution

                             V₁C₁   =  V₂C₂

Solve for V₁ (original solution)

                                 V₁ = \frac{V2C2}{C1}

Substitution

                                V₁ = \frac{(0.5)(100)}{4}

Simplification

                                V₁ = \frac{50}{4}

Result

                                V₁ = 12.5 ml

7 0
3 years ago
A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}

Where,

m_{solute} = Given mass of solute (KOH) = 3.301 g

M_{solute} = Molar mass of solute (KOH) = 56.1 g/mol

W_{solvent} = Mass of solvent = 96.699 g

Putting values in above equation, we get:

\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m

Hence, the molality of potassium hydroxide solution is 0.608 m

4 0
3 years ago
0.0145 moles of helium gas are introduced into a balloon so that the volume of the balloon is 2.54 liters. An additional amount
olga_2 [115]

Answer:

4.43L is final volume of the ballon

Explanation:

Avogadro's law of ideal gases states that <em>equal volumes of gases, at the same temperature and pressure, have the same number of molecules</em>.

The formula is:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

Where V and n are volume and moles of the gas in initial and final conditions.

If the initial conditions are 0.0145 moles and 2.54L and final amount of moles is 0.0253moles, final volume is:

\frac{2.54L}{0.0145mol} =\frac{V_2}{0.0253mol}

V₂ = <em>4.43L is final volume of the ballon</em>

6 0
3 years ago
guys im morgz im going to put a nail on the seat in my mom room and im going to see how up her a- s s it will go lets see
vagabundo [1.1K]

Answer:

go outside and ponder your life choices dork.

6 0
3 years ago
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