Answer:
1384 kJ/mol
Explanation:
The heat absorbed by the calorimeter is equal to the heat released due to the combustion of the organic compound. C is the total heat capacity of the calorimeter and Δt is the change in temperature from intial to final:
Q = CΔt = (3576 J°C⁻¹)(30.589°C - 25.000°C) = 19986.264 J
Extra significant figures are kept to avoid round-off errors.
We then calculate the moles of the organic compound:
(0.6654 g)(mol/46.07) = 0.0144432 mol
We then calculate the heat released per mole and convert to the proper units. (The conversion between kJ and J is infinitely precise and is not involved in the consideration of significant figures)
(19986.264 J)(1kJ/1000J) / (0.0144432 mol) = 1384 kJ/mol
Hello!
If there's an air bubble inside the buret, and the bubble escapes the buret during the titration the initial volume lecture (Vi) would be lower (closer to 0) than the actual one, and the recorded consumed volume (ΔV=Vf-Vi) would be higher than the actual one and thus the calculated concentration of the hydrochloric acid would be higher than the real one.
Have a nice day!
Answer:
so the number of molecules in 8 moles of water is 4.8176×10^24
Explanation:
number of moles=8moles
avogadro's number=6.022×10²³
number of molecules=?
as we know that
substituting the equation
number of moles × avogdro's number=number of molecules
number of molecules=8moles×6.022×10²³
number of molecules=4.8176×10^24
i hope this will help you :)
Answer:
The answer to your question is 1.36 x 10²³ atoms
Explanation:
Data
number of atoms = ?
mass of the sample = 34.2 g
Molecule = Cl₂O₅
Process
1.- Calculate the molar mass of Cl₂O₅
Cl₂O₅ = (35.5 x 2) + (16 x 5) = 71 + 80 = 151 g
2.- Calculate the atoms of Cl₂O₅
151 g of Cl₂O₅ ---------------- 6 .023 x 10²³ atoms
34.2 g of Cl₂O₅ ------------ x
x = (34.2 x 6.023 x 10²³) / 151
x = 1.36 x 10²³ atoms
Answer:
My bad i didnt mean to put that carry on.
Explanation:
