Which of the following is not a heterogeneous mixture? a. concrete b. pizza c. sugar water d. chicken soup

12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1

uranmaximum [27]

Answer:

Wavelength, $\lambda=3.3\times 10^{-18}\ m$

Explanation:

We have,

Velocity of the object, $v=5\times 10^5\ m/s$

Mass of the object, $m=4\times 10^{-22}\ kg$

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

$\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m$

So, the wavelength of the object is $3.3\times 10^{-18}\ m$ .

5 0

3 years ago

Why do ionic compounds conduct when dissolved and covalent compounds do not?

Wewaii [24]

Lo siento ... necesito puntos!......

4 0

3 years ago

Calculate the density mass= 54.2 volume= 78.1

Helen [10]

Answer:

0.693 (you can round it up if you want to)

Explanation:

Density= mass ÷ volume

54.2 ÷ 78.1 = 0.693

I hope this helped☺

6 0

3 years ago

State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3

Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

5 0

2 years ago