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iogann1982 [59]
3 years ago
14

Stemscopedia

Chemistry
1 answer:
Alexeev081 [22]3 years ago
7 0
What’s the question
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What is it called when scientists write out a compound such as two hydrogen and one oxygen? PLEASE HELP
schepotkina [342]
A compound is when two or more elements are joined together. The compound that is created with two hydrogens and one oxygen is h2o or water.
7 0
3 years ago
Which of these processes involves the splitting of an Atom
Sever21 [200]
Nuclear fossion hope this helps
3 0
3 years ago
Read 2 more answers
What does it mean to say an equation is balanced? Why is it important for an equation to be balanced?​
Rom4ik [11]

Answer: It is important for an equation to be balanced because if it is not then the reactants won't match the products.

Explanation: I don't know if you will understand this but here:

Let's say you're cooking eggs, you're reactants so to speak would be 3 eggs and 1 tablespoon of oil so you put it together using heat and a pan. Your products have to match what you have in the beginning. You cannot have an equation that looks like this

Reactants = 3eggs + 1Tbsp oil ---pan/heat---> 6eggs + 1 cup of oil

You cannot get something from what you don't have. The number of how much of an element you have must be the same of both sides of the equation.

8 0
1 year ago
What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute
sergeinik [125]
Moles = n/v where n is the moles of solute and v being the liters of solution.
We can put in the information provided to find the molarity.

Moles = .45/3.0 = .15
So we now know that the molarity of that solution is .15!
 I hope I helped you :). Make sure to memorize that formula because it's not that hard as long as you know what to plug in.
6 0
3 years ago
Read 2 more answers
Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has
bija089 [108]
<h2>Answer:</h2>

Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic  \: mass }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 72 \times84.9 + 28 \times 87  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 6112.8 + 2436  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 8548.8  }{100} \\

\footnotesize \longrightarrow \:  \bf Average \:  atomic  \: mass =  85.488 \: amu  \\

8 0
2 years ago
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