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slamgirl [31]
2 years ago
13

Determine the percent composition by mass of a 100g salt solution which contains 20g salt

Chemistry
2 answers:
prisoha [69]2 years ago
8 0

Answer:

Mass of solution=100g

mass of salt=20g

so; mass of solute=80g

percentage composition =(mass of salt/total

mass) ×100

=  \frac{20}{100}  \times 100 \\  = 20\%

glad to help you

hope it helps

lara [203]2 years ago
8 0

The percent composition by mass of a 100g salt solution which contains 20g salt is \bold{16.6\%}

<u>Solution:</u>  

Percent composition is calculated as, weight of the solute divided by amount of solute added to 100 g is solution multiplied by 100.

\Rightarrow \frac{\text {weight of solute}(g)}{\text {weight of solute}(g)+\text {weight of solution(g)}} \times 100

Given, 100 g of salt solution with 20 g of salt  

Weight of the solute and solvent is 20 + 100 g = 120 g  

percent composition=\frac{20}{120} \times 100=\frac{200}{12}=16.6

\therefore \text { percent composition } =16.6 \%

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4.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1
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Answer:

\mathbf{C_{10}H_8}   ( Naphthalene )

Explanation:

Given that:

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Compound X undergoes combustion reaction and the product yield :

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H_2O with mass 2.53 g

The objective is to use this information to determine the molecular formula of X.

We all know that ; number of moles = mass/molar mass

where the molar mass of H_2O is 18 g/mol

number of moles of H_2O product = 2.53 g/18 g/mol

number of moles of H_2O product = 0.1406 moles

Also; the molar mass of CO_2 product = 44 g/mol

number of moles of CO_2 product = 15.47g/ 44 g/mol

number of moles of CO_2 product =  0.3516 moles

number of moles of Compound X in the reactant side= 4.50 g /128 g/mol

number of moles of Compound X n the reactant side= 0.03516 moles

Now; number number of moles of CO_2 in reactant = 0.3516 moles/0.03516 moles

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number of moles of H_2O reactant = 7.997 ≅ 8

Since we said the Compound X is known to be made of Carbon C , Hydrogen H and Oxygen O

Then the molecular formula can be written as :

\mathbf{C_{10}H_8O_{x}}

In order to find the x; we have

128  = (12 × 10 + 1 × 8 + 16 × x)

128 = 120 + 8 + 16x)

128  =  128 + 16 x

128 - 128 = 16 x

0 = 16 x

x = 0/16

x = 0

As x = 0 ; hence there are no oxygen present in the reaction

Thus; the molecular formula of Compound X = \mathbf{C_{10}H_8} which is also known as Naphthalene

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