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3 years ago

Simplify 20+4(3x−5)+2x=28

Mathematics

1 answer:

Solnce55 [7]3 years ago

5 0

Answer: x=2

Step-by-step explanation:

20+4(3x-5)+2x=28

We move all terms to the left:

20+4(3x-5)+2x-(28)=0

We add all the numbers together, and all the variables

2x+4(3x-5)-8=0

We multiply parentheses

2x+12x-20-8=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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Answer:

(A) The percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B) The problem solving time will be 50% as long as the difference between the two end points is 5.75.

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Let the random variable X represent the time it takes the technician to resolve the problem.

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The probability density function of X is:

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(A)

Compute the probability that the problems takes more than 5 minutes to resolve as follows:

$P(X>5)=\int\limits^{12}_{5}{\frac{1}{12-0.50}}\, dx$

$=\frac{1}{11.50}\cdot \int\limits^{12}_{5}{1}\, dx \\\\=\frac{1}{11.50}\cdot [x]\limits^{12}_{5}\\\\=\frac{1}{11.50}\cdot [12-5]\\\\=\frac{7}{11.50}\\\\=0.608696\\\\\approx 0.6087$

Thus, the percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B)

Let the middle 50% of the problem-solving times be between u and v.

Then,

P (u < X < v) = 0.50

$\int\limits^{v}_{u}{\frac{1}{12-0.50}}\, dx=0.50\\\\\frac{1}{11.50}\cdot \int\limits^{v}_{u}{1}\, dx=0.50\\\\\frac{v-u}{11.50}=0.50\\\\(v-u)=5.75$

Thus, the problem solving time will be 50% as long as the difference between the two end points is 5.75.

(C)

The interval in which the technician can solve the problem is 30 seconds to 12 minutes.

So, the values of a and b in minutes is:

a = 30 seconds = 0.50 minutes

b = 12 minutes.

(D)

The mean time is:

$\mu=\frac{a+b}{2}=\frac{0.50+12}{2}=6.25\ \text{minutes}$

The standard deviation of the time is:

$\sigma=\sqrt{\frac{(b-a)^{2}}{12}}=\sqrt{\frac{(12-0.50)^{2}}{12}}=3.3197\approx 3.32\ \text{minutes}$

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