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Molodets [167]
3 years ago
10

What is the significance of enzymes in maintaining homeostasis in living organisms ?

Chemistry
1 answer:
GalinKa [24]3 years ago
7 0
 Enzymes are needed for metabolic pathways in the body, respiration, digestion and other important life processes. When enzymes function properly, homeostasis is maintained. However, if an enzyme is lacking or has an incorrect shape due to genetic mutation, this can lead to disease within an organism.
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Identify reagents necessary to convert cyclohexane into 1,3-cylohexadiene: notice that the starting material has no leaving grou
Vinvika [58]
<span>1,3-cylohexadiene i synthesized starting from cyclohexane in following 4 steps.

1) Free Radical Substitution Rxn:
 Halogenation of cyclohexane in the presence of UV yield chlorocyclohexane.

2) Elimination Rxn: Dehydrohalogenation of chlorocyclohexane yields cyclohexene.

3) Halogenation of Cyclohexene (Electrophillic Addition Rxn) gives 1,2-dihalocyclohexane.

4) Elemination Rxn: When dibromocyclohexane is treated with KOH and heated it gives 1,3-cyclohexadiene as shown below,</span>

4 0
3 years ago
Which of the following statements are FALSE of models? (select all that applies)
ira [324]

Answer:

A B and C

Explanation:

Hopefully this helps

7 0
3 years ago
(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe
Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration C_o = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

time (t) = \dfrac{V}{Q}

time (t) = \dfrac{200}{0.3}

time (t) = 666.66 \ sec

time (t) = \dfrac{666.66 }{3600} hrs

time (t) = 0.185 hrs

\text{Using First Order Reaction:}

\dfrac{dc}{dt}=kc

where;

t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)

0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)

0.942 =  \Big ( \dfrac{200}{C_e}- 1 \Big)

1+ 0.942 =  \Big ( \dfrac{200}{C_e} \Big)

\dfrac{200}{C_e} = 1.942

C_e = \dfrac{200}{1.942}

\mathbf{C_e = 102.98 \ mg/l}

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]

\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)

\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)

\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)

V_{PFR} =0.196(0.663)*0.3*3600

V_{PFR} = 140.34 \ m^3

The volume of the PFR is ≅ 140 m³

3 0
3 years ago
Coefficients are used in a chemical formula to show the number of each element. True or False
ANTONII [103]

Answer:

The same number of each element present before the reaction takes place must also be present on the product side of the equation. Coefficients are placed in front of a chemical formula to show the number of moles of that substances that are necessary for the reaction to occur.

Explanation:

5 0
3 years ago
The gas that a diver breathes must be maintained at a partial pressure of 0.20 atm of oxygen. More oxygen could poison the diver
Nimfa-mama [501]

<u>Answer:</u> The partial pressure of helium gas is 0.80 atm

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of helium gas, we use the law given by Dalton, which is:

P_T=p_{He}+p_{O_2}

We are given:

Total pressure of the cylinder, P_T = 1.00 atm

Vapor pressure of oxygen gas, p_{O_2} = 0.20 atm

Putting values in above equation, we get:

1.00=p_{He}+0.20\\\\p_{He}=1.00-0.20=0.80atm

Hence, the partial pressure of helium gas is 0.80 atm

5 0
3 years ago
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