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lord [1]
2 years ago
13

Is the answer 1.05m?? help me please. i just want to confrim my answer :3

Physics
1 answer:
grandymaker [24]2 years ago
4 0
I believe you are correct! Have a good day! <3
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8. A student does 1,000 J of work when she moves to her dormitory. Her internal energy is decreased by 3,000 J. Determine the he
Lyrx [107]

Answer:

The heat loss during the process = -4000 J

Explanation:

Work done by the student (W) = - 1000 J

Negative sign on the system is due to work done on the system.

Decrease in internal energy (U) = - 3000 J

We know that heat transfer in the system is given by (Q) = U + W

⇒ Q = - 1000 - 3000

⇒ Q = - 4000 J

This is the value of heat transfer during the process And negative sign indicates that heat loss during the process.

6 0
3 years ago
A force of 350N is applied to a body. If the work done is 40kJ, what is the distance through which the body moved?
Studentka2010 [4]

The distance covered by the body is 114.3 m

Explanation:

The work done by a force exerted on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the object in this problem, we have

F = 350 N is the force applied

W=40 kJ = 40,000 J is the work done

\theta=0^{\circ} if we assume that the force is applied parallel to the motion of the object

Solving for d, we find the distance covered by the object:

d=\frac{W}{F cos \theta}=\frac{40,000}{(350)(cos 0)}=114.3 m

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
The sketch below shows some of the insides of a stereo speaker. Running current through the wire, which is wrapped around the ba
VARVARA [1.3K]

Energy transformation, also termed as energy conversion, is the process of changing energy from one of its forms into another. In physics, energy is a quantity that provides the capacity to perform many works—think of lifting or warming an object. In addition to being convertible, energy is transferable to a different location or object, but it cannot be created or destroyed.


Energy in many of its forms may be used in natural processes, or to provide some service to society such as heating, refrigeration, lighting or performing mechanical work to operate machines. For example, in order to heat your home, your furnace can burn fuel, whose chemical potential energy is thus converted into thermal energy, which is then transferred to your home's air in order to raise its temperature.


In another example, an internal combustion engine burns gasoline to create pressure that pushes the pistons, thus performing work in order to accelerate your vehicle, ultimately converting the fuel's chemical energy to your vehicle's additional kinetic energy corresponding to its increase in speed.

Contents


   1 Entropy and limitations in conversion of thermal energy to other types

   2 Transformation of kinetic energy of charged particles to electric energy

   3 History of energy transformation from the early universe

   4 Examples

       4.1 Examples of sets of energy conversions in machines

       4.2 Other energy conversions

   5 See also

   6 References



3 0
3 years ago
Read 2 more answers
Does Anybody Know The Answers?
ch4aika [34]

Answer:

I was going to give you the paper where I saw it but since you are not giving enough points I can not give you so I am only going to give you some of these that are here sorry

Explanation:

1.

9^{2} + 12^2 = x^2\\81 + 144= x^2\\\sqrt{225} = \sqrt{x} \\         15=x\\\\ 2.\\x^2+12^2+=13^2\\x^2+144 =169\\x^2 = 25\\\sqrt{x^2 =\sqrt{25\\\\

x=5

3.\\12^2+32^2 = x^2\\34.176= x

7.

5,12,13

9.

\frac{x}{4} ,\frac{12}{4} ,\frac{20}{4}\\\\\frac{x}{4},3,5  \\\\x=16\\\\12. \\x^2 + 48^2=50^2\\\\x^2=196\\x=14

Download docx
5 0
2 years ago
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

⇒  \frac{1}{R_{net}} =\frac{3}{6}

⇒  \frac{1}{R_{net}} =\frac{1}{2}

On applying cross-multiplication, we get

⇒ R_{net}=2 \Omega

3 0
3 years ago
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