Question

A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through the block the bullet slows to 60 m/s. What is the final velocity of the block of wood after the bullet passes through? (No mass is lost)

Answer 1

Answer:

The final velocity of the wooden block is equal to $1.035 m/s$

Explanation:

Given that mass of bullet = $m_{b} = 0.025kg$

                Mass of wood = $m_{w} = 7kg$

               Initial velocity of bullet = $u_{b} = 350m/s$

              Final velocity of bullet = $v_{b} = 60m/s$

               Initial velocity of wood = o

               Final velocity of wood = $v_{w]$

   Here momentum is conserved so initial momentum = final momentum

            $m_{b}u_{b} = m_{b} v_{b} + m_{w}v_{w}$ .

    Upon substituting these values in above equation , we get

        $v_{w} = 1.035m/s$.