False . accelerating means to increase but moving at a constant speed means you stay the same .
Given:
10^10 electrons per second
To justify that coulomb is a very large unit for practical use, we need to convert the quantity of electron given to Coulombs:
From literature,
1 Coulomb is equivalent to 6.242×10^18 electrons<span>.
So,
= 10^10 electrons * (1 coulomb/</span><span>6.242×10^18</span> electrons) / second
<span>= 1.602 x 10^-9 coulumbs
This value is too small to be used in an actual setting.
</span><span>
</span>
Answer:
Newtons
Explanation:
Magnitude of charge on the electron = q =
Coulombs
The negative sign in the question statement indicates that the charge is negative.
Magnitude of Electric Field experienced by the electron = E =
Newtons/Coulomb
Magnitude of Force on the electron = F = ?
The relation between the charge, electric field and the force on the charge because of electric field is given by:

From here we can write:
F = qE
Using the values, we get:

Thus, the magnitude of the electric force experience by the electron would be
Newtons
Answer:
Option D - 0.2 s
Explanation:
We are given;
Initial velocity; u = 7 m/s
Height of table; h = 1.8m
Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.
Thus;
h = ut + ½gt²
Plugging in the relevant values, we have;
1.8 = 7t + ½(9.8)t²
4.9t² + 7t - 1.8 = 0
Using quadratic formula to find the roots of the equation gives us;
t = -1.65 or 0.22
We can't have negative t value, thus we will pick the positive one.
So, t = 0.22 s
This is approximately 0.2 s
D). located out side the nucleus