Answer:
<em> think 2 also if not im so sorry but i think it is :)</em>
Answer:
the initial velocity of the car is 12.04 m/s
Explanation:
Given;
force applied by the break, f = 1,398 N
distance moved by the car before stopping, d = 25 m
weight of the car, W = 4,729 N
The mass of the car is calculated as;
W = mg
m = W/g
m = (4,729) / (9.81)
m = 482.06 kg
The deceleration of the car when the force was applied;
-F = ma
a = -F/m
a = -1,398 / 482.06
a = -2.9 m/s²
The initial velocity of the car is calculated as;
v² = u² + 2ad
where;
v is the final velocity of the car at the point it stops = 0
u is the initial velocity of the car before the break was applied
0 = u² + 2(-a)d
0 = u² - 2ad
u² = 2ad
u = √2ad
u = √(2 x 2.9 x 25)
u =√(145)
u = 12.04 m/s
Therefore, the initial velocity of the car is 12.04 m/s
Explanation:
The atoms of elements such as hydrogen, sodium and potassium have only one electron in their outermost electron shell while atoms such as calcium, iron and chromium have several loosely held electrons. The bond would be almost entirely covalent. Ionic bonds form between atoms of very different electronegativities, e.g. sodium and chlorine, in which case the electron is largely removed from the sodium atom and transferred to the chlorine atom, resulting in sodium(+) chloride(-) ionic bonding