The answer is square root of 46. The first two are somewhere in between 5 and the last one is after 7. C was the only one that lied in 6.7
Answer:
1. 285 2. 2 795 3. 26 320
Step-by-step explanation:
19
<u>x 15</u>
95
<u> 190</u>
285
To get the 95, multiply 9 x 5, which is 45. Then, carry over the 4 and multiply 1 x 5, which is 5. Add 5 + 4, which is 9, so then you have 95.
To get the 190, you first have to write a 0 in the unit's place because we are working with the tens. Then, you multiply 9 x 1, which is 9. You then multiply
1 x 1, which is 1.
For the final step, you add 95 + 190 = 285 and this is your answer.
Answer:
The tree is about 8 feet.
Step-by-step explanation:
7 2/3 = 7.6 as a fraction.
30 1/5 = 30.5 as a fraction.
Know, we must divide 30.5 by 7.6.
30.5 ÷ 7.6 = 4 when rounded to the nearest whole number.
Since we know that the stake is 2 feet, we must multiply this by 4, since the other shadow is 4 times the amount of the stake.
2 x 4 = 8
This means the tree is about 8 feet.
Answer:
The component form of the velocity of the airplane is
.
Step-by-step explanation:
Let suppose that a bearing of 0 degrees corresponds with the
direction and that angle is measured counterclockwise. Besides, we must know both the magnitude of velocity (
), in miles per hour, and the direction of the airplane (
), in sexagesimal degrees to construct the respective vector. The component form of the velocity of the airplane is equivalent to <u>a vector in rectangular form with physical units</u>, that is:
(1)
If we know that
and
, then the component form of the velocity of the airplane is:
![\vec v = 389.711\,\hat{i} -225\,\hat{j}\,\left[\frac{m}{s} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20389.711%5C%2C%5Chat%7Bi%7D%20-225%5C%2C%5Chat%7Bj%7D%5C%2C%5Cleft%5B%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%5D)
The component form of the velocity of the airplane is
.
Answer:
The following outlines a general guideline for factoring polynomials:
Check for common factors. If the terms have common factors, then factor out the greatest common factor (GCF).
Determine the number of terms in the polynomial. ...
Look for factors that can be factored further.
Check by multiplying.
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