Question

1) How much water must be added to 500.mL of 0.200 M HCI to produce a 0.150M solution?

Answer 1

Answer:

1)

(500.mL)(.200M)/.150M = 667 mL

667mL - 500mL = 167mL of water is needed

2)

1.0 L = 1000mL

M1 V1 = M2 V2

(1.6 mol/L) (175 mL) = (x)(1000mL)

x = .28M