2 years ago

1) How much water must be added to 500.mL of 0.200 M HCI to produce a 0.150M solution?

Chemistry

1 answer:

zloy xaker [14]2 years ago

6 0

Answer:

(500.mL)(.200M)/.150M = 667 mL

667mL - 500mL = 167mL of water is needed

1.0 L = 1000mL

M1 V1 = M2 V2

(1.6 mol/L) (175 mL) = (x)(1000mL)

x = .28M

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