For i: 33mL
For ii: 87-88mL
For iii:22.3mL
Answer:
e. 3
Explanation:
In order to solve this problem we need to keep in mind the definition of pH:
As stated by the problem, the hydrogen ion concentration, [H⁺], is 1x10⁻³ M.
As all required information is available, we now can <u>calculate the pH</u>:
The correct option is thus e.
Answer:
0.29mol/L or 0.29moldm⁻³
Explanation:
Given parameters:
Mass of MgSO₄ = 122g
Volume of solution = 3.5L
Molarity is simply the concentration of substances in a solution.
Molarity = number of moles/ Volume
>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.
Number of moles = mass/ molar mass
Molar mass of MgSO₄:
Atomic masses: Mg = 24g
S = 32g
O = 16g
Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol
= (24 + 32 + 64)g/mol
= 120g/mol
Number of moles = 122/120 = 1.02mol
>>>> From the given number of moles we can evaluate the Molarity using this equation:
Molarity = number of moles/ Volume
Molarity of MgSO₄ = 1.02mol/3.5L
= 0.29mol/L
IL = 1dm³
The Molarity of MgSO₄ = 0.29moldm⁻³
This is what i have found i hope this helps
8
It’s 8 bc I said it was 8 ;)
