The mass (in grams) of the silicon present in the computer chip is 2.19 g
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of Si
But
1 mole of Si = 28 g
Thus, we can say that:
6.02×10²³ atoms = 28 g of Si
- With the above information, we can obtain the mass of silicon, Si present in the computer chip. This can be obtained:
6.02×10²³ atoms = 28 g of Si
Therefore,
4.71×10²² atoms = (4.71×10²² × 28) / 6.02×10²³ g of Si
4.71×10²² atoms = 2.19 g of Si
Thus, the mass of silicon, Si present in the computer chip is 2.19 g
Learn more on Avogadro's number: brainly.com/question/25811549
Your answer is 2 goes to the right and twice to the left
16.00 grams of oxygen
since in one mole the mass would be the molecular mass, which is found on the periodic table
<em>Here is the Answer I Hope this Helps:-</em>
<em>The closer the electrons are to the nucleus, the more tightly they are bound, thus increasing the electronegativity of the atom.</em>