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Montano1993 [528]
3 years ago
12

How many of each element are present in this compound 4C4HgCL​

Chemistry
1 answer:
frozen [14]3 years ago
5 0

Answer:

Percent Composition of Compounds

The percent composition (by mass) of a compound can be calculated by dividing the mass of each element by the total mass of the compound.

LEARNING OBJECTIVES

Translate between a molecular formula of a compound and its percent composition by mass

  • The atomic composition of chemical compounds can be described in a variety of ways, including molecular formulas and percent composition.
  • The percent composition of a compound is calculated with the molecular formula: divide the mass of each element found in one mole of the compound by the total molar mass of the compound.
  • The percent composition of a compound can be measured experimentally, and these values can be used to determine the empirical formula of a compound.

  • percent by mass: The fraction, by weight, of one element of a compound.
  • The atomic composition of chemical compounds can be described using a variety of notations including molecular, empirical, and structural formulas. Another convenient way to describe atomic composition is to examine the percent composition of a compound by mass.

  • Percent Composition by Mass

Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

Explanation:

I hope it's help

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Answer:
number of dozens = 4.35834 * 10^21 dozens

Explanation:
A dozen contains 12 atoms. To know the number of dozens containing
5.23 * 10^22 atoms, all we have to do is cross multiplication as follows:
1 dozen ...........> 12 atoms
?? dozens ......> <span>5.23 * 10^22 
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number of dozens = 4.35834 * 10^21 dozens

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How can I differentiate between Ionic compounds, molecular compounds, and acids given only the formula? I need to be able to fin
VikaD [51]
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Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.
Oduvanchick [21]

Answer:

103.9 g

Explanation:

  • C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First <u>we convert 54.0 g of propane (C₃H₈) into moles</u>, using its <em>molar mass</em>:

  • 54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we <u>convert 1.23 moles of C₃H₈ into moles of CO₂</u>, using the <em>stoichiometric coefficients</em>:

  • 1.23 mol C₃H₈ * \frac{3molCO_2}{1molC_3H_8} = 3.69 mol CO₂

We <u>convert 3.69 moles of CO₂ into grams</u>, using its <em>molar mass</em>:

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And <u>apply the given yield</u>:

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Explanation:

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