Answer:
0.98 M
Explanation:
Given data:
Mass of sugar = 20 g
Mass of water = 59 g
Concentration of solution = ?
Solution:
1 g = 0.01 L
59 g× 0.01 L/1 g
0.059 L
Concentration formula:
C = m/v
m = moles of solute
v = volume of solution
Number of moles of sugar:
Number of moles = mass/molar mass
Number of moles = 20 g/ 342.3 g/mol
Number of moles = 0.058 mol
Now we will calculate the concentration:
C = 0.058 mol/0.059 L
C = 0.98 mol/L
C = 0.98 M
Answer: 20
Explanation: there you go my freind
Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:
where n = number density
Substituting for P, k and T in equation (2) gives:
Next, substituting for n and σ in equation (1) gives:
Answer:
The molar mass of is 96.8 g/mol
Explanation:
The given molecular formula -
Individual molar masses of each element in the compound is as follows.
Molar mass of nitrogen - 14.01 g/mol
Molar mass of of hydrogen = 1.008g/mol
Molar mass of carbon = 12.01 g/mol
Molar mass of oxygen =16.00 g/mol
Molar mass of is
Therefore,The molar mass of is 96.8 g/mol
count the elements in eqn MgI2 + Br2 -> MgBr2 + I2
1 Mg, 2I, 2Br on the left n
1 Mg, 2I, 2Br on the right
they are equal so the eqn is balanced