The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), butanoic aci
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<u>Answer:</u> The volume of NaOH required is 402.9 mL
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
- <u>For HCl:</u>
Molarity of HCl solution = 0.315 M
Volume of solution = 503.4 mL = 0.5034 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
- <u>For sulfuric acid:</u>
Molarity of sulfuric acid solution = 0.125 M
Volume of solution = 503.4 mL = 0.5034 L
Putting values in equation 1, we get:
As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles
Molarity of NaOH solution = 0.55 M
Moles of NaOH = 0.2216 moles
Putting values in equation 1, we get:
Hence, the volume of NaOH required is 402.9 mL