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nlexa [21]
3 years ago
15

A researcher measures the equilibrium separation between two flat hydrophilic mica plates in a solution of non-ionic surfactant.

When the surfactant concentration is below CMC the surfaces touch at 0 nm distance without any separation (i.e., there is no surfactant adsorption and repulsion)
a) The researcher increases the surfactant concentration much above CMC and finds out that the system has equilibrium separations at 0 nm, 4 nm, 8 nm, 12 nm and some at larger distances. Draw schematics and explain the reason for this effect.
b) The researcher hydrophobizes the mica surfaces and again dips them in the first solution with surfactant concentration below CMC. When these surfaces are brought in contact, they remain separated at a distance of 4 nm (no equilibria at larger separations). Draw a schematic and explain the reason for this observation with hydrophobic surfaces.

Chemistry
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

See explaination and attachment

Explanation:

please kindly see attachment for the step by step solution of the given problem.

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Answer: me

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5 0
3 years ago
Calculate the molarity of a solution consisting of 25.0 g of KOH in 3.00 L of solution.
melomori [17]

Answer:

0.15M

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

You need to calculate the number of moles from the given grams. The molar mass of KOH is (39.098+ 16 +1.008)= 56.106g. To calculate the mols of KOH, \frac{25.0g}{1} × \frac{1 mol}{56.106g} = 0.44558... mol, you see that the grams unit cancel out leaving you with mol as the unit.

The volume is given in L already so no need to do any conversion. M= \frac{0.4558mol}{3.00L} = 0.1485M ≈ 0.15M

5 0
2 years ago
A 0.2688 g sample of a monoprotic acid neutralized 16.4 mL of 0.08133 M KOH solution. Calculate the molar mass of the acid
ivanzaharov [21]

Answer:

202 g/mol

Explanation:

Let's consider the neutralization between a generic monoprotic acid and KOH.

HA + KOH → KA + H₂O

The moles of KOH that reacted are:

0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol

The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.

1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:

0.2688 g/1.33 × 10⁻³ mol = 202 g/mol

3 0
3 years ago
Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

4 0
2 years ago
Which of these is most likely to form between elements transferring electrons to
Stella [2.4K]

Answer: The answer is an ionic bond

6 0
3 years ago
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