Answer:
the length of the shortest ladder is 11.41 feet
Step-by-step explanation:
The computation of the length of the shortest ladder is shown below:
AB^2 = AC^2 + BC^2
AB^2= (10)^2 + (5.5)^2
AB^2= 100 + 30.25
AB^2 = 130.25
AB = 11.41 feet
hence, the length of the shortest ladder is 11.41 feet
Answer:
Final answer is approx x=0.16.
Step-by-step explanation:
Given equation is ![2.8\times 13^{4x} +4.8 = 19.3](https://tex.z-dn.net/?f=2.8%5Ctimes%2013%5E%7B4x%7D%20%2B4.8%20%3D%2019.3)
Now we need to solve equation
and round to the nearest hundredth.
![2.8\times 13^{4x} +4.8 = 19.3](https://tex.z-dn.net/?f=2.8%5Ctimes%2013%5E%7B4x%7D%20%2B4.8%20%3D%2019.3)
![2.8\times 13^{4x} = 19.3-4.8](https://tex.z-dn.net/?f=2.8%5Ctimes%2013%5E%7B4x%7D%20%3D%2019.3-4.8%20)
![2.8\times 13^{4x} = 14.5](https://tex.z-dn.net/?f=2.8%5Ctimes%2013%5E%7B4x%7D%20%3D%2014.5%20)
![13^{4x} = \frac{14.5}{2.8}](https://tex.z-dn.net/?f=13%5E%7B4x%7D%20%3D%20%5Cfrac%7B14.5%7D%7B2.8%7D%20)
![13^{4x} = 5.17857142857](https://tex.z-dn.net/?f=13%5E%7B4x%7D%20%3D%205.17857142857%20)
![\log(13^{4x}) = \log(5.17857142857)](https://tex.z-dn.net/?f=%5Clog%2813%5E%7B4x%7D%29%20%3D%20%5Clog%285.17857142857%29%20)
![4x \log(13) = \log(5.17857142857)](https://tex.z-dn.net/?f=4x%20%5Clog%2813%29%20%3D%20%5Clog%285.17857142857%29%20)
![4x = \frac{\log(5.17857142857)}{\log\left(13\right)}](https://tex.z-dn.net/?f=4x%20%3D%20%5Cfrac%7B%5Clog%285.17857142857%29%7D%7B%5Clog%5Cleft%2813%5Cright%29%7D%20)
![4x = 0.641154659628](https://tex.z-dn.net/?f=4x%20%3D%200.641154659628%20)
![x = \frac{0.641154659628}{4}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B0.641154659628%7D%7B4%7D%20)
![x = 0.160288664907](https://tex.z-dn.net/?f=x%20%3D%200.160288664907%20)
Round to the nearest hundredth.
Hence final answer is approx x=0.16.
Answer:
1 7/8
Step-by-step explanation:
dont know lol but trust me
Jessica will need to continue knitting for 4 nights.
9cm - 1cm = 8cm
8cm / 2cm = 4 nights
Hope this helps: If it did, please mark brainliest, give a thanks, and rate it five stars! [I'm two brainliests away from moving up!] Have an amazing rest of your day and stay safe! Let me know if you need anymore help! xx
To calculate the square root, you can either use the √symbol on a calculator or you can manually find it using Prime Factorization. For non-perfect squares, Prime Factorization is the way to go.
The first two steps work for solving large perfect squares as well.
1. Divide your number into perfect square factors.
2. Take the square roots of your perfect square factors.
3. If your number doesn't factor perfectly, reduce your answer to simplest terms.
4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be.
ie.
![\sqrt{63}](https://tex.z-dn.net/?f=%20%5Csqrt%7B63%7D%20)
you know that
![7^2 =49](https://tex.z-dn.net/?f=7%5E2%20%3D49)
and
![8^2 = 64](https://tex.z-dn.net/?f=8%5E2%20%3D%2064)
, so you can estimate that the
![\sqrt{63}](https://tex.z-dn.net/?f=%20%5Csqrt%7B63%7D%20)
would be between 7 and 8 but closer to 8.
5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie. </span>
![\sqrt{45}](https://tex.z-dn.net/?f=%20%5Csqrt%7B45%7D%20)
=
![\sqrt{9*5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B9%2A5%7D%20)
=
![\sqrt{3*3*5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B3%2A3%2A5%7D%20)
=
![3 \sqrt{5}](https://tex.z-dn.net/?f=3%20%5Csqrt%7B5%7D%20)
Hope this helped!!!