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likoan [24]
2 years ago
11

Calculate the mass on the following pic

Physics
2 answers:
Iteru [2.4K]2 years ago
3 0

Answer:

<em>1.</em> 25 <em> 2</em>. 3.75  <em>3.</em> 21.5

Explanation:

M=FxA

1. 5x5

2. 5x.75

3. 5x4.3

the force on all is 5n

Alex777 [14]2 years ago
3 0
Same as this other guy said mark him Brainleis
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Answer:

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2 years ago
Your mom is making lunch which forces are acting on your mom
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The forces acting on your mom while cooking is Air resistance and the force of friction

<u>Explanation:</u>

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<u>2. The force of friction:</u>

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7 0
3 years ago
Read 2 more answers
A long solenoid with 1.65 103 turns per meter and radius 2.00 cm carries an oscillating current I = 6.00 sin 90πt, where I is in
Leno4ka [110]

Answer:

The  electric field  is 35\cos(90\pi t)\ mV/m

Explanation:

Given that,

Radius = 2.00 cm

Number of turns per unit length n= 1.65\times10^{3}

Current I = 6.00\sin 90\pi t

We need to calculate the induced emf

\epsilon =\mu_{0}nA\dfrac{dI}{dt}

Where, n = number of turns per unit length

A = area of cross section

\dfrac{dI}{dt}=rate of current

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E=\dfrac{\epsilon}{2\pi r}

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E=\dfrac{\mu_{0}nA\dfrac{dI}{dt}}{2\pi r}....(II)

We need to calculate the rate of current

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On differentiating equation (III)

\dfrac{dI}{dt}=90\pi\times6.00\cos(90\pi t)

Now, put the value of rate of current in equation (II)

E=\dfrac{4\pi\times10^{-7}\times1.65\times10^{3}\times\pi\times(2.00\times10^{-2})^2\times90\pi\times6.00\cos(90\pi t)}{2\pi\times 2.00\times10^{-2}}

E=35\cos(90\pi t)\ mV/m

Hence, The  electric field  is 35\cos(90\pi t)\ mV/m

7 0
2 years ago
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