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RideAnS [48]
3 years ago
6

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance

to measure the force between two lead spheres whose centers were 0.29 m apart. One of the spheres had a mass of 148 kg, while the mass of the other sphere was 0.63 kg.What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

1.198*10^{-8}

Explanation:

The law of gravitation has to be used in this question along with Newton's second law

Ratio = \frac{Gravitational force}{weight of the smaller sphere}= \frac{\frac{6.674*10^{-11*148*0.63} }{0.29^{2} } }{0.63 kg * 9.8} = 1.198*10^{-8}

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An uncharged capacitor is connected to a 21-V battery until it is fully charged, after which it is disconnected from the battery
attashe74 [19]

Answer:

The voltage bewtween the plates will be 9.5V

Explanation:

Facts:

The capacitance of a parallel plate capacitor having plate area A and plate separation d is C=ϵ0A/d.  

Where ϵ0 is the permittivity of free space.  

A capacitor filled with dielectric slab of dielectric constant K, will have a new capacitance C1=ϵ0kA/d

        C1=K(ϵ0A/d)

        C1=KC   ----------- 1

Where C is the capacitance with no dielectric and C1 is the capacitance with dielectric.

The new capacitance is k times the capacitance of the capacitor without dielectric slab.  

This implies that the charge storing capacity of a capacitor increases k times that of the capacitor without dielectric slab.

Given points

• The terminal voltage of the battery to which the capacitor is connected to charge V=25V

• A dielectric slab of paraffin of dielectric constant K=2  is inserted in the space between the capacitor plates after the fully charged capacitor is disconnected

The charge stored in the original capacitor Q=CV

The charge stored in the original capacitor after inserting dielectric Q1=C1V1

The law of conservation of energy states that the energy stored is constant:

i.e Charge stored in the original capacitor is same as charge stored after the dielectric is inserted.

Q   =  Q1

CV = C1V1

  CV = C1V1  -------2

We derived C1=KC from equation 1. Inserting this into equation 2

   CV = KCV1

 V1 = (CV)/KC

         V/K

       = 21/2.2

      = 9.5

4 0
3 years ago
Which of the following pieces of laboratory equipment is not directly used to make measurements
RoseWind [281]
I believe the answer is a test tube.
4 0
3 years ago
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In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of th
Tamiku [17]

Answer:

2.124 kg of water

Explanation:

height of the falls is about 48 meters.

Mass of water needed is 1kg = 1000g

Power needed is 106 watts.

The amount of energy in 106 watts in one sec is 106 joules.

To calculate the energy of the 1kg falling water = Mgh

Energy = 1000*9.81*48

Energy = 470880 joules.

1 megawatt is = 1000000watts

The kilogram of water needed is 1000000/470880 = 2.124 kg of water

3 0
3 years ago
What does the wavelength of visible light waves correspond to?
marissa [1.9K]

Explanation:

Visible light is a very part of electromagnetic spectrum. We can see the visible region of the electromagnetic spectrum.

The frequency and the wavelength has an inverse relationship.

For example, the red light has large wavelength and low frequency. Violet has a short wavelength and higher frequency.

The frequency range of visible region is from 400 nm to 700 nm.

7 0
3 years ago
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I NEED HELP Quick PLEASE AND THANK YOU !!!
luda_lava [24]
Well if u see here the graph is showing us 1.5 on the graph so we multiply that by 6 and we get 46 as our final anwser
3 0
3 years ago
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