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RideAnS [48]
3 years ago
6

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance

to measure the force between two lead spheres whose centers were 0.29 m apart. One of the spheres had a mass of 148 kg, while the mass of the other sphere was 0.63 kg.What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

1.198*10^{-8}

Explanation:

The law of gravitation has to be used in this question along with Newton's second law

Ratio = \frac{Gravitational force}{weight of the smaller sphere}= \frac{\frac{6.674*10^{-11*148*0.63} }{0.29^{2} } }{0.63 kg * 9.8} = 1.198*10^{-8}

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A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
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Answer:

0.099C

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V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

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V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

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Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
A particle moves with a velocity    1 v 5j 3j 6k ms      under influence of a contact force  F 10i 10j 20k N.    
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Answer:

P = 200 W

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We apply this equation to our case where the velocity is

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Answer:

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