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RideAnS [48]
3 years ago
6

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance

to measure the force between two lead spheres whose centers were 0.29 m apart. One of the spheres had a mass of 148 kg, while the mass of the other sphere was 0.63 kg.What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

1.198*10^{-8}

Explanation:

The law of gravitation has to be used in this question along with Newton's second law

Ratio = \frac{Gravitational force}{weight of the smaller sphere}= \frac{\frac{6.674*10^{-11*148*0.63} }{0.29^{2} } }{0.63 kg * 9.8} = 1.198*10^{-8}

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3 years ago
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ololo11 [35]

Answer:

A & D

Explanation:

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From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

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6 0
2 years ago
Read 2 more answers
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Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
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To learn more about Energy please visit -
brainly.com/question/27671072
#SPJ1

8 0
2 years ago
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hope it helps you!!

6 0
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