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Kipish [7]
2 years ago
15

Paper thickness varies. Typically, 100 sheets are about a cm thick. Atoms typically vary from 1 to 3 angstroms in radius. (An an

gstrom is 10-10 m.) Suppose a piece of paper is 0.0072 cm thick. How many atoms span the thickness if the radius of the atom is 1.23 angstroms
Chemistry
1 answer:
MrMuchimi2 years ago
6 0

Answer:

292683

Explanation:

Thickness of a piece of paper = 0.0072 cm

Radius of an atom = 1.23\ \AA

Conversion factor of \AA to \text{cm} is

1\ \AA=1\times 10^{-10}\ \text{m}=1\times 10^{-8}\ \text{cm}

Diameter of an atom = 2\times 1.23\times 10^{-8}=2.46\times 10^{-8}\ \text{cm}

Number of atoms in one piece of paper is

\dfrac{0.0072}{2.46\times 10^{-8}}=292682.92\approx 292683

Hence, the number of atoms in one piece of paper is 292683.

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